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natka813 [3]
3 years ago
10

Need help, due ASAP. Please help.

Mathematics
1 answer:
omeli [17]3 years ago
4 0

Answer:

a = 36.37 cm

c = 18.19 cm

Step-by-step explanation:

to find a, use tan

⇒ tan = \frac{opposite}{adjacent}

⇒ tan 60 = \frac{21}{a}

tan of 60 is 1.732

⇒ 1.732 = \frac{21}{a}

multiply 21 on both sides

⇒ 1.732 x 21 = \frac{21}{a}x 21

⇒ 36.37 = a

to find c, use sine

⇒ sine = \frac{oppsosite}{hypotenuse}

⇒ sine 60 = \frac{21}{c}

sine of 60 is 0.866

⇒ 0.866 = \frac{21}{c}

muliply 21 on both sides

⇒ 0.866 x 21 = \frac{21}{c} x 21

⇒ 18.19 = c

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A letter is randomly chosen from the word EXCELLENT. Write each probability as a fraction, decimal, and a percent.
Sergio [31]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. A complete question is in the form:

A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.

Solution:

The total number of letters found in the word EXCELLENT = 9

i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3

Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3

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ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6

Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3

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Evaluate and simplify the expression<br> when a = 4 and b = -1.<br> 5 - 2(a + 3b)/2
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Answer:

4

Step-by-step explanation:

hope it helps ;)

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3 years ago
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