For this case we have that the weight of the bouquet of flowers will be:
4.3 * 10 ^ 4 - 2 * (7.5 * 10 ^ 2)
Rewriting we have:
4.1 * 10 ^ 4 miligrams
Thus, we have that the values of p and q are given by:
p = 4.1
q = 4
Answer:
4.1 * 10 ^ 4 miligrams
p = 4.1
q = 4
Answer:
The answer is "152 ft"
Step-by-step explanation:
Please find the attached file.
The area of the square 
can be found on the foot.
The area of the triangular front will then be calculated 
Since each has two sides, 
.
Therefore the multiplying the area of the bottom square 
by the number of cells to get 152.
The following statements are considered to be propositions:
- There are more men than women at BYU-Idaho.
<h3>What is deductive reasoning?</h3>
Deductive reasoning can be defined as a type of logical reasoning that typically involves drawing conclusions based on a given set of rules and conditions or from one or more premises (factual statements) that are assumed to be generally (universally) true.
<h3>What is a proposition?</h3>
A proposition can be defined as a type of statement (assertion) that is typically used to express an opinion or a judgement, with either a true or false answer.
This ultimately implies that, a proposition refers to a type of statement (assertion) that is either a true or false.
In this context, we can infer and logically deduce that the following statements are considered to be propositions:
- There are more men than women at BYU-Idaho.
Read more on propositions here: brainly.com/question/24158168
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Let t be the number of tolls they crossed.
Amount they spent at each toll = $1.75.
Amount they spent at gas station = $28.
Let C be the total amount they spent on gas and tolls.
If they crossed 1 toll, then
C = 28 + 1.75(1).
If they crossed 3 tolls, then,
C = 28 + 1.75(3)
If they crossed t tolls, then,
C = 28 + 1.75t
Here, the terms are 28 and 1.75t and the factors are 1.75 and t.
The equation you would use to find her earning for the week would be:
y=0.03(x-1000)+150
This would mean she made $66 from commissions and $216 total.
