The complete factorisation of 50a²b⁵ − 35a⁴b³ + 5a³b⁴ is 5a²b³(10b² - 7a² + ab)
<h3>How to factorise?</h3>
Factorisation is the process of writing an expression as a product of two or more common factors.
The expression is written as a product of several factor.
Therefore,
50a²b⁵ − 35a⁴b³ + 5a³b⁴
Hence, the complete factorisation is as follows;
5a²b³(10b² - 7a² + ab)
learn more on factorisation here: brainly.com/question/2272501
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Is that x squared? Cause if so then the answer would be f= 5
Answer:
The current is 34 mph in still water, I think I could be wrong.
Answer:
(1,-3.7)
Step-by-step explanation:
subtract the y axis to go down
5 - 8.7 = -3.7
Using polynomial long division, we get
3x^3+6x^2+11x
_____________
(x+2) | 3x^4-x^2+cx-2
-(3x^4+6x^3)
____________
6x^3-x^2+cx-2
- (6x^3+12x^2)
_____________
11x^2+cx-2
-(11x^2+22x)
__________
(22+c)x-2.
If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.
For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
