2 answers:
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Answer:
Follows are the solution to these question:
Explanation:
A simple gullible algorithm is present. Let h mark the house to the left. Then we put a base station about 4 kilometers to the right. Now delete and repeat all the houses protected by this base station. In this algorithm, they can simply be seen to position baselines at b1, . . , bk as well as other algorithms (which may be an optimum algorithm) at and so on. (from left to right)
That's why
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Following are the program to calculate even digits sum:
<h3>Program:</h3>#include <iostream>//header file
using namespace std;
int main()//main method
{
int a[10],s=0,i;//defining an array and an integer variable
cout<<"Enter array values: ";//print message
for(i=0;i<=9;i++)//defining a loop that input array value
{
cin>>a[i];//input array value
}
for(int i=0;i<=9;i++)//defining loop that check array value
{
if(a[i]%2==0)//defining if block that checks even number condition value
{
s=s+a[i];//adding even number value
}
}
cout<<"The sum of even number is: "<<s;//print even number sum value
return 0;
}
Program Explanation:
- Defining a header file.
- Defining the main method.
- Inside the main method, an integer array "a", and two integer variable "s,i" is declared.
- In the next step, a for loop is declared that input the array value, and after input value another loop is declared that check even number value in array.
- In this loop it adds array value and after adding the value a print method is declared that prints its value.
Output:
Please find the attached file.
Find out more information about the even number here:
