Answer:
Explanation:
Algorithm design is the branch of discrete mathematics and computer science that deals with the research, development and implementation of sequential and asynchronous algorithms. ... An algorithm is simply a sequence of instructions; a recipe is an algorithm, and so is a list of driving instructions.
My name is Chris I'm sorry for being so late but no I got it and I will be there for being such a great time with you and your team and I will get back to you are you still looking I'm sorry for being a little bump it to the only thing I can think of is that a little bit of time
Answer:
Have water by, have it organized, and have notes by you welcome.
Explanation:
Answer:
3) A Single linked list is a sequence of elements in which every element has link to its next element in the sequence.
DATA LINK
DATA stores actual value , LINK stores address of next node
As per information given in question, letters at the even addresses are items in linked list and the odd addresses will be used as links.
Even Address Odd Address
12 (Stores 't') 13 (Used as link)
14 (Stores 'm') 15 (Used as link)
16 (Stores 'a') 17 (Used as link)
18 (Stores 'r') 19 (Used as link)
20 (Stores 's') 21 (Used as link)
Numbers represented by circle are addresses of respective nodes. Here Front or Head has address 16. Which represents the Head Node.
Following image represents the word "smart" with respective nodes and their addressing.
Numbers represented by circle are addresses of respective nodes.
The head pointer is: 20
Answer:
(a)The CPU B should be selected for the new computer as it has a low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A.
(b) The CPU B is faster because it executes the same number of instruction in a lesser time than the CPU A
.
Explanation:
Solution
(a)With regards to the MIPS performance metric the CPU B should be chosen for the new computer as it low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A and when we look at the amount of process done by the system , the CPU B is faster when compared to other CPU and carries out same number of instruction in time.
The metric of response time for CPU B is lower than the CPU A and it has advantage over the other CPU and it has better amount as compared to CPU A, as CPU B is carrying out more execution is particular amount of time.
(b) The execution can be computed as follows:
Clock cycles taken for a program to finish * increased by the clock cycle time = the Clock cycles for a program * Clock cycle time
Thus
CPU A= 5*10^6 * 60*10^-9 →300*10^-3 →0.3 second (1 nano seconds =10^-9 second)
CPU B= 3 *10^6 * 75*10^-9 → 225*10^-3 → 0.225 second
Therefore,The CPU B is faster as it is executing the same number of instruction in a lesser time than the CPU A
