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Firlakuza [10]
3 years ago
12

A botanist is collecting data from a particular species of plant. The scientist found that the data is normally distributed with

a mean value of =147 μ = 147 cm and standard deviation of =30 σ = 30 cm. If the sample size is =4000 N = 4000 how many specimens have a height greater than 73 73 cm
Mathematics
1 answer:
SashulF [63]3 years ago
5 0

Answer:

3972.72 specimens

Step-by-step explanation:

We solve using the z score formula:

z = (x-μ)/σ where

x is the raw score = 73 cm

μ is the population mean = 147 cm

σ is the population standard deviation = 30 cm

N is the number of samples = 4000

For x > 73

z = 73 - 147/30

z = -2.46667

Probability value from Z-Table:

P(x<73) = 0.0068189

P(x>73) = 1 - P(x<73) = 0.99318

The probability of having a height greater than 73cm is: 0.99318

The number of specimens that have a height greater than 73cm is calculated as: 0.99318 × 4000

= 3972.72 specimens

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M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
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Therefore the required polynomial is

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Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

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Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

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3 years ago
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