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Firlakuza [10]
3 years ago
12

A botanist is collecting data from a particular species of plant. The scientist found that the data is normally distributed with

a mean value of =147 μ = 147 cm and standard deviation of =30 σ = 30 cm. If the sample size is =4000 N = 4000 how many specimens have a height greater than 73 73 cm
Mathematics
1 answer:
SashulF [63]3 years ago
5 0

Answer:

3972.72 specimens

Step-by-step explanation:

We solve using the z score formula:

z = (x-μ)/σ where

x is the raw score = 73 cm

μ is the population mean = 147 cm

σ is the population standard deviation = 30 cm

N is the number of samples = 4000

For x > 73

z = 73 - 147/30

z = -2.46667

Probability value from Z-Table:

P(x<73) = 0.0068189

P(x>73) = 1 - P(x<73) = 0.99318

The probability of having a height greater than 73cm is: 0.99318

The number of specimens that have a height greater than 73cm is calculated as: 0.99318 × 4000

= 3972.72 specimens

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The box plot shows the ages of people at a movie screening. What percent of the people are between 20 and 37 years old?
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What will be the remainder when 6x ^5+ 4x^4 -27x^
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Answer:

Remainder = (3145/8)x - 408

Step-by-step explanation:

We want to find the remainder when 6x^(5) + 4x⁴ - 27x³ - 7x² + 27x + 3/2 is divided by (2x² - 3)²

Let's expand (2x² - 3)² to give ;

(2x - 3)(2x - 3) = 4x² - 6x - 6x + 9 = 4x² - 12x + 9

So,we can divide now;

______________________

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First of all, we'll divide the term with the highest power inside the long division symbol by the term with the highest power outside the division symbol. This will give;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

We now subtract the new multiplied term beneath the original one from the original one to get;

3/2x³

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³+27x +3/2

We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

(3/2)x³ + (11/2)x²

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

(3/2)x³ + (11/2)x²

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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______________________

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6x^(5)-18x⁴-(27/2)x³

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22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

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______________________

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6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(159/2)x³-(113/2)x²+27x+(3/2)

(159/2)x³-(477/2)x²+(1431/8)x

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

182x²-(1215/8)x + (3/2)

We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

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______________________

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22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

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(159/2)x³-(113/2)x²+27x+(3/2)

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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6 0
4 years ago
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Mice21 [21]

Answer:

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Step-by-step explanation:

Correct word <em>"We turned a $25,000 investment of money in 1982 into $100,000 in 2007."  What return (interest rate) did they really earn on their investment?</em>

No of years(1982 to 2007) = 25 years

The average annual return is R%, so $25,000 * (1 + R)^25 = $100,000

(1 + R)^25 = $100,000 / $25,000

(1 + R)^25 = 4

<em>We take 25th root on each side</em>

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1 + R = 1.0570

R = 1.0570 - 1

R = 0.057

R = 5.70%

So, the return (interest rate) they really earn on their investment is 5.70%.

7 0
3 years ago
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