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3 years ago

2. Last year, Springfield Middle School had 620

Mathematics

2 answers:

elena-s [515]3 years ago

6 0

Answer: A

Step-by-step explanation: In all logic its only a 40 soemthing difference and its a bigger number so my guess is 6.1

timama [110]3 years ago

4 0

C i think, sorry if its wrong

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Pls help and do quick!

motikmotik

Answer:

If 50.24cm = Circumference

Radius = 8cm

If 50.24cm^2 = Area

Radius = 4cm

Step-by-step explanation:

50.24cm what? Circumference? Area?

π = 3.14

2πr = Circumference

50.24 / 2π = r

r = 8

πr^2 = Area

50.24 / π = r^2

r^2 = 16

r = 4

7 0

2 years ago

How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

3 years ago

In the triangle,sum of two angles is 90° which is the measure of the third angle. Also,the difference of these 2 angle is 10°, f

Alona [7]

<h2><em>Hey friend, Here is your answer in the picture. </em></h2><h2><em> </em></h2><h2><em>The measure of the two angles is 50° and 40° </em></h2><h2><em> </em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!!</em></h2>