it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
Find out more at: brainly.com/question/11535666
The answer to this question is 48.
The figure on the top left is a triangle with base 11 and height 8, for an area of
Immediately below, we have a rectangle with dimensions 11 and 9, for an area of
Moving to the right, we have a parallelogram with base 9 and heght 11, which again has height
Finally, the rightmost figure is a triangle with base 8 and height 9, for a total of
Sum these areas and you'll get the total area
First subtract y from both sides to isolate the variable.
25 = 2y-2
Next, add 2 to both sides.
27 = 2y
Last, divide by 2.
13.5 = y
