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2 years ago

Hey!! What is 3% of 130? First to answer correct will get brainliest!!

Mathematics

2 answers:

timofeeve [1]2 years ago

7 0

Answer:

3.9

Step-by-step explanation:

0.03 × 130 = N

3.9 = N

Hope this helps!

expeople1 [14]2 years ago

4 0

Answer:

The answer is 3.9 :)

Step-by-step explanation:

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Match each quadratic equation with its solution set

Sever21 [200]

Hello,
Please, see the attached files.
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4 0

3 years ago

In the diagram below, BC−→− bisects ∠FBE

nirvana33 [79]

Answer:

m∠EBC = 34°

Step-by-step explanation:

m∠DBC = m∠DBE + m∠ EBC

m∠DBC - m∠DBE = m∠EBC

(12x - 3)° - (5x + 12)° = (3x + 13)°

12x - 5x - 3 - 12 = 3x + 13

4x = 28

x = 7

m∠EBC = (3(7) + 13)° = 34° 

7 0

2 years ago

Determine if the side lengths could form a triangle. Use an inequality to prove your answer.

podryga [215]

9514 1404 393

Answer:

a) no

b) yes

c) maybe (no)

Step-by-step explanation:

There are two versions of the triangle inequality. One requires ...

a + b > c

for any triple of side measures a, b, c.

The other allows ...

a + b ≥ c

which admits "triangles" that have zero height and look like line segments.

Most questions asking "do these lengths form a triangle" are concerned with the "greater than" case, and disallow the "or equal to" case.

$16+21=37\ngtr39\qquad\text{not a triangle}$

$27+34=61>58\qquad\text{could be a triangle}$

$9+29=38\ge38\qquad\text{could be a triangle if "equal to" is allowed}$

7 0

2 years ago

Find mZP. P 26 2./13 R mZP = I’m confused

kondaur [170]

Answer:

45 degrees

Step-by-step explanation:

Since we have a right triangle, we use the appropriate trigonometric ratio

The angle marked P faces QR and that makes it the opposite side

PR faces the right angle and that makes it the hypotenuse

The trigonometric ratio that links the opposite and the hypotenuse is the sine

It is the ratio of the opposite to the hypotenuse

Thus;

sin P = √26/2 √13

Sin P = √2/2

P = arc sin √2/2

P = 45 degrees

8 0

3 years ago

What are the exact values of sin theta cos theta tan theta if (3,-4) is a point on the terminal side of theta?

malfutka [58]

$\bf (\stackrel{a}{3}~,~\stackrel{b}{-4})\impliedby \textit{now let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{3^2+(-4)^2}\implies c=\sqrt{25}\implies \boxed{c=5}$

$\bf -------------------------------\\\\
sin(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\qquad cos(\theta )=\cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{5}}\qquad tan(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{adjacent}{3}}$

6 0

3 years ago