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drek231 [11]
2 years ago
15

Help and if you actually answer I'll give you brainliest​

Mathematics
2 answers:
ololo11 [35]2 years ago
7 0

Answer:

4/6 = 2/3

2/4 = 1/2

12/15 = 4/5

6/8 = 3/4

pretty sure this is correct. hope it helps!

schepotkina [342]2 years ago
6 0

Answer:

1) 2/3

2) 1/2

3) 4/5

4) 3/4

Step-by-step explanation:

4/6 can be divided by 2 to get 2/3 in its simplest

2/4 can be divided by 2 to get 1/2 in its simplest

12/15 can be divided by 3 to get 4/5 in its simplest

6/8 can be divided by 2 to get 3/4 in its simplest

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Jen invested $3500 into a continuously compounded account with an interest rate of 3.1%. After 9 years, how much money is in the
GarryVolchara [31]

Answer:

≈$4607

Step-by-step explanation:

I will assume it's compounded yearly.

Apply the compound interest formula.

A=P(1+\frac{r}{n})^{nt}

A = Total

P = Initial Principle

r = Interest Rate

n = number of interest in every t period

t = number of periods

In the case,

P = 3500

r = 3.1% = 0.031

n = 1

t = 9

Hence,

A=3500(1+\frac{0.031}{1})^{1*9}

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2 years ago
Analyze the following computer password in terms of how secure it might be. Describe the criteria you use in determining its str
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7 0
3 years ago
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I need help !!!!!! Please bZ÷12=9
scoundrel [369]

Answer:

The answer is b=18/z

Step-by-step explanation:

Let's solve for b.

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5 0
3 years ago
2 more questions thanks
sergey [27]
These are two questions and two answers.

1) Problem 17.

(i) Determine whether T is continuous at 6061.

For that  you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.

a) T(x) = 0.10x if 0 < x ≤ 6061

T (6061) = 0.10(6061) = 606.1

b) limit of Tx when x → 6061.

By the left the limit is the same value of T(x) calculated above.

By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)

⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10

Since both limits and the value of the function are the same, T is continuous at 6061.

(ii) Determine whether T is continuous at 32,473.

Same procedure.

a) Value at 32,473

T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26

b) Limit of T(x) when x → 32,473 from the right

Limit = 5360.26 + 0.26(x - 32,473) = 5360.26

Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.

(iii) If  T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.

2) Problem 18.

a) Statement Sk

You just need to replace n for k:

Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2

b) Statement S (k+1)

Replace

S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2

Simplification:

1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2

                 k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2

Do the operations on the left side and  you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.

With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.

4 0
2 years ago
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