PLEASE PLEASE PLEASE PLEASE PLEASE HELP If sin B= 0.5678, what is the measure of

Can someone solve this? The answer needs to be in fraction form so can't be done by a calculator.

Lesechka [4]

Answer:

9 1/6

You may use a fraction calulator for this question by the way!

Hope this helps!

Sorry if its wrong!

Have a nice day!

7 0

3 years ago

How to factorise the difference of perfect squares. for the g on the top and j on the top

Fed [463]

Answer:

see explanation

Step-by-step explanation:

A difference of two squares is factored as

a² - b² = (a - b)(a + b)

(g)

1 - 81y²

= 1² - (9y)²

= (1 - 9y)(1 + 9y)

(j)

64x² - 25y²

= (8x)² - (5y)²

= (8x - 5y)(8x + 5y)

7 0

3 years ago

What is the interquartile range (IQR) of this data set?

Andreas93 [3]

Answer:

11 is the median of the entire data set

6 is the median of the lower half and 16 is the median of the upper half data scores...

Subtract 16 from 6 gives 10 so the answer is C) 10

7 0

2 years ago

Read 2 more answers

Look at the picture

Sonbull [250]

$\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \frac{9(|x-8|)}{9} < \frac{36}{9} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}$

$\underline{\boldsymbol{\sf{Answer}}}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }$

$\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \ correct \ option}} \ \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}$

6 0

2 years ago

Please hurry and answer this for me. willing to give 15 points.

arlik [135]

Answer: Range - 12 Median - 59

Step-by-step explanation: To find the range order your numbers from least to greatest then subtract the smallest from the highest 61-49 = 12 then for the median do the same in ordering the numbers then count how many you have. The number in the middle is your median. If there is two add them and divided by two. 59. Hope this helped!

8 0

2 years ago