When a non volatile solute is added to a solvent, the vapor pressure of the solvent will decrease.
Vapor pressure is a colligative property. Which means that it will be affected by the number of particles of solute.
The relationship between the concentration of the solute and the vapor pressure is given by Roult's Law
ΔP = Xsolute * P, where ΔP is vapor pressure lowering, Xsolute is the molar fractionof the solute, and P is the vapor pressure of the solvent.
Then lets find Xsolute
X solute = # moles solute / # moles solution
# moles solute = 75.0 grams / molar mass
molar mass of C12H22O11 = 12*12g/mol + 22*1g/mol + 11*16g/mol = 342 g/mol
# moles solute = 75.0/342 mol = 0.219 mol
# moles of solvent = grams of solvent / molar mass of solvent
# moles of solvent = 180 grams /18 g/mol = 10 mols
Xsolute = 0.219 mol solute / (10 + 0.219) mol solution =0.0215
ΔP = 0.0215*26.7 torr = 0.57 torr
Answer= 0.57 torr
Answer:
fluorine (f) lies in group 17 and 2 period
There are 2 Ca, 4 H (2*2) and 4 O (2+2) on the left hand side. So there should be the same number of atoms 2Ca and 4(O+H) on the right hand side. The reaction is a synthesis (making something new), rather than a decomposition (destroying something).
The answer is Two molecules of Ca(OH)2 should be produced during the synthesis reaction.
Answer:
pH = 11.7
Explanation:
<u>Given:</u>
[OH-] = 0.00500 M
<u>To determine:</u>
pH of the solution
<u>Explanation:</u>
pH refers to the H+ ion concentration in a given solution whereas pOH indicates the OH- ion concentration.
pH and pOH are related by the following equation:
![pH + pOH = 14 ------(1)](https://tex.z-dn.net/?f=pH%20%2B%20pOH%20%3D%2014%20------%281%29)
Here:
![pH = -log[H+]\\\\pOH = -log[OH-]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%2B%5D%5C%5C%5C%5CpOH%20%3D%20-log%5BOH-%5D)
When OH- = 0.00500 M
![pOH = -log(0.00500) = 2.30\\](https://tex.z-dn.net/?f=pOH%20%3D%20-log%280.00500%29%20%3D%202.30%5C%5C)
Based on equation(1):
![pH = 14 - pOH = 14 -2.30=11.7](https://tex.z-dn.net/?f=pH%20%3D%2014%20-%20pOH%20%3D%2014%20-2.30%3D11.7)
Answer:
When water temperature increases (right), the rate of evaporation also increases. In turn, the amount of water vapor in the "air space" above the water increases. ... But, with increased evaporation, more water molecules exist in the air above the water, which in turn increases the condensation rate.