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kupik [55]
3 years ago
11

For each of the reactions provided, write a balanced equation. Then, using your knowledge of reaction types and the activity ser

ies as needed, explain what type of reaction occurred and/or how you determined that a reaction occurred.
a. A strip of magnesium is added to a solution of silver nitrate.
b. A solution of copper(II) chloride is added to a solution of sodium sulfide.
c. Sodium oxide and water are formed from sodium hydroxide.
Chemistry
1 answer:
pshichka [43]3 years ago
5 0

Answer:

a.monadioxide

Explanation:

for maintaince of different gases in the air to separate reactions of chemicals

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Which of the following is NOT true regarding Rutherford's Gold Foil experiment?
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Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.

Hope this info is useful.

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What are the functional groups in oxybenzone?
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Oxybenzone contains ether, phenol and ketone (-CO) functional group alonq with two aromatic rings.

Explanation:

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6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?
Eddi Din [679]

Answer:

 12120 g  +    O2        =    15084 g

m Zn = 12.120 Kg

m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2.  calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) =  ( 1210 g / 15084 g ) x 100

% m/m (Zn) = 80.35 % = 80.35 g

%m/m (O) =  ( 2964 g / 15084 g ) x 100

% m/m (Zn) = 19.65 %  = 19.65 g

4. Calcular moles de cada elemento

Zn: 80.35 g / 65.38 g/mol = 1.228 mol

O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

Zn: 1.228 mol / 1.228 mol = 1

O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

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3 years ago
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Vsevolod [243]

Answer:

study the natural world

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Predict how many grams of KCI is produced from 40 grams of K?
Nutka1998 [239]

Explanation:

firstly find for the molar mass of kcl and molar mass of k

and then

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