The correct answer choice from the statement above about investigated factors from lab results is :
Students who spend less time studying after school get lower math grade
Option D is the correct answer
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Answer:
0.324 g is required to make 5.00 M solution of NaCl in 0.800 L.
Given data:
Molarity = 5.00 M
Formula Mass = 58.5 g/mol
Required volume = 0.800 L
To Find;
Mass in gram = ?
Solution:
Formula for calculating mass in gram is given as,
Mass in gram = Molarity × Formula mass × Volume required / 1000 putting values
Mass in gram = 5.00 M × 58.5 g/mol × 0.800 L / 1000
Mass in gram = 0.234 g
Answer: 4 molL-1
Explanation:
Detailed solution is shown in the image attached. The number of moles of NaCl is first obtained. Since the molarity must be in units of molL-1, the volume is divided by 1000 and the formula stated in the solution is applied and the answer is given to one significant figure.
Answer:
0.135 mole of H2.
Explanation:
We'll begin by calculating the number of mole in 3.24 g of Mg. This can be obtained as follow:
Mass of Mg = 3.24 g
Molar mass of Mg = 24 g/mol
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 3.24/24
Mole of Mg = 0.135 mole
Next, we shall write the balanced equation for the reaction. This is illustrated below:
Mg + 2HCl —> MgCl2 + H2
From the balanced equation above,
1 mole of Mg reacted to produce 1 mole of H2.
Finally, we shall determine the number of mole of H2 produced by reacting 3.24 g (i.e 0.135 mole) of Mg. This can be obtained as follow:
From the balanced equation above,
1 mole of Mg reacted to produce 1 mole of H2.
Therefore, 0.135 mole of Mg will also react to produce 0.135 mole of H2.
Thus, 0.135 mole of H2 can be obtained from the reaction.