A line with a slope of 0 passes through the point (6, 16). What is its equation in slope-intercept form?

Mathematics

1 answer:

satela [25.4K]2 years ago

8 0

Answer:

y = 0x + 16

Step-by-step explanation:

Slope of line m = 0

$(6,\:16)=(x_1,\:y_1)$

Equation of line in slope point slope form is given as:

$y-y_1 = m(x-x_1) \\\\\therefore y - 16 = 0(x - 6)\\\\\therefore y - 16 = 0x - 0\\\\\therefore y = 0x + 16\\\\$

This is the required equation in slope intercept form.

You might be interested in

James and Sarah went out to lunch. The price of lunch for both of them was $20. They tipped their server 15% of that amount.

Wittaler [7]

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 20}}{\left( \cfrac{15}{100} \right)20}\implies 3~\hfill \begin{array}{llll} \stackrel{\textit{price + tip}}{20+3\implies 23}\\\\ \stackrel{\textit{each one paid half of 23}}{11.5} \end{array}$