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3 years ago

What is 77/200 as a decimal

1 answer:

8 0

The correct answer is 0.385.

Explanation:
Decimals deal with powers of 10, such as 10, 100, 1000, etc. We can change this to a power of 10 by dividing both top and bottom by 2; this will give us 100 in the denominator.

77/2=38.5, so we have 38.5/100.

Dividing by 100 is the same as moving the decimal two places to the left, so we have 0.385.

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The graph of the function F(x) = 2x^2-8 is changed. The new graph can be

vova2212 [387]

Answer:

The graph now opens in the opposite direction. The y intercept is shifted up 4.

Step-by-step explanation:

F(x) = 2x^2-8

F(X)= -2x^2-4

We know that the graph is reflected over the y-intercept becuase of the negative sign in the second equation ( F(X)= -2x^2-4)

We know that the intercept is shifted up four, because the number decreased from 8 to 4, and the graph is reflected.

Attacthed is both of the equations graphed to help you visualize this shift!

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3 years ago

F(x) = x2 - 6x + 13

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Answer:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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worty [1.4K]

Answer:

a) N

b) L

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d) area II

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Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

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3 years ago

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LenaWriter [7]

Answer:

the answers you chose are correct.

Step-by-step explanation

b and d

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2 years ago