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Alecsey [184]
3 years ago
11

What is 77/200 as a decimal

Mathematics
1 answer:
garri49 [273]3 years ago
8 0
<span>The correct answer is 0.385.

Explanation<span>:
Decimals deal with powers of 10, such as 10, 100, 1000, etc. We can change this to a power of 10 by dividing both top and bottom by 2; this will give us 100 in the denominator.

77/2=38.5, so we have 38.5/100.

Dividing by 100 is the same as moving the decimal two places to the left, so we have 0.385.</span></span>
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Answer:

The radius of the circle is 3.5 inches.

Step-by-step explanation:

The radius is half the diameter:R= 1/2 d

Substitute the value of d (7 inches) in the formula to find r:

r= 1/2 x 7 in

r= 3.5 in

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dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is  -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4


14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0


15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x


16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

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4 years ago
A bag consist of 4 blue marbles and 6 red marbles. Three marbles are randomly selected from the bag with replacement after each
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2/25  

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Answer:

The vector equation

r = (2 + 3t)i+ (2.4 + 2t)j+ (3.5   - t)k

The parametric equation

x = 2 + 3t\\y = 2.4 + 2t\\z = 3.5-t

Step-by-step explanation:

Given

Point  = (2,2.4,3.5)

Vector = 3i + 2j - k

Required

The vector equation

First, we calculate the position vector of the point.

This is represented as:

r_0 = 2i + 2.4j + 3.5k

The vector equation is then calculated as:

r = r_o + t * Vector

r = 2i + 2.4j + 3.5k + t * (3i + 2j - k)

Open bracket

r = 2i + 2.4j + 3.5k + 3ti + 2tj - tk

Collect like terms

r = 2i + 3ti+ 2.4j + 2tj+ 3.5k   - tk

Factorize

r = (2 + 3t)i+ (2.4 + 2t)j+ (3.5   - t)k

The parametric equation is represented as:

x = x_0 + at\\y = y_0 + bt\\z = z_0 + ct

Where

r = (x_0 + at)i +(y_0 + bt)j+(z_0 + ct)k

By comparison:

x = 2 + 3t\\y = 2.4 + 2t\\z = 3.5-t

4 0
3 years ago
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