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Vedmedyk [2.9K]
3 years ago
11

3a+b=225 b=a-15 first step

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

60 = a

Step-by-step explanation:

I attached a pic of how I got 60 = a

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Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad
Zigmanuir [339]

Answer:

\theta = 5.83\ rad

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

\omega_f^2 = \omega_i^2 + 2 \alpha \theta

0 = \omega_i^2 - 2\times 0.5\times 6.1

\omega_i = \sqrt{6.1}

\omega_i = 2.47\ rad/s

now, angular position calculation at t=3.9 s

\theta = \omega_i t + \dfrac{1}{2}\alpha t^2

\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2

\theta = 5.83\ rad

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

7 0
3 years ago
the height, h cm, of a table is measured s 72cm correct to the nearest centimeters. conplete the following statement to show the
gogolik [260]
Anything between 71.5 and 72.499 recurring.

Hope this helps :)
6 0
3 years ago
Which is the value of this expression when j = negative 2 and k = negative 1?
Natalija [7]

Answer:

Option A.

Step-by-step explanation:

It is given that

j=-2, k=-1

The given expression is

\left(\dfrac{jk^{-2}}{j^{-1}k^{-3}}\right)^3

Substitute the given values in the above expression.

\left(\dfrac{(-2)(-1)^{-2}}{(-2)^{-1}(-1)^{-3}}\right)^3

\Rightarrow \left(\dfrac{(-2)(1)}{\dfrac{1}{-2}(-1)}\right)^3

\Rightarrow \left(\dfrac{-2}{\dfrac{1}{2}}\right)^3

\Rightarrow \left(-4\right)^3

\Rightarrow -64

Therefore, the correct option is A.

3 0
3 years ago
Read 2 more answers
The population standard deviation for the typing speeds for secretaries is 4 words per minute. If we want to be 90% confident th
Oksana_A [137]

Answer:

The minimum sample size that should be taken is 62.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

If we want to be 90% confident that the sample mean is within 1 word per minute of the true population mean, what is the minimum sample size that should be taken

This is n when M = 1, \sigma = 4. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.96*\frac{4}{\sqrt{n}}

\sqrt{n} = 4*1.96

(\sqrt{n})^{2} = (4*1.96)^{2}

n = 61.5

The minimum sample size that should be taken is 62.

8 0
3 years ago
Suppose that the local sales tax rate is 6.25% and you purchased a used car for $16,800. What is the car’s total cost?
Tanzania [10]
Total= Car Cost + (Car Cost * Tax %)

Total= $16,800 + ($16,800 * 6.25%)
convert % to decimal form; divide % by 100

Total= $16,800 + ($16,800 * 0.0625)
multiply inside parentheses

Total= $16,800 + $1,050

Total= $17,850


ANSWER: The total cost for the used car with tax is $17,850.

Hopd this helps! :)
7 0
3 years ago
Read 2 more answers
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