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kogti [31]
3 years ago
7

Which bodies of water in the list are found to the west of the Philippines?​

Chemistry
1 answer:
bogdanovich [222]3 years ago
3 0

Answer:

South China sea

Explanation:

To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).

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4) What is the mass of 5.20 moles of sodium bicarbonate, NaHCO3? Hint: To solve this problem
inysia [295]
The mass is 437 g NaHCO3 and this is my work shown

8 0
3 years ago
A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what
ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
2 years ago
Based on the article, how would you define a heat sink?
tigry1 [53]

Answer:

Glad you know what it is now!

Explanation:

Nice!!

7 0
3 years ago
Read 2 more answers
What is the correct term for the breakdown of organic sediment into phosphorous
viktelen [127]

Answer: Phosphorous Cycle

5 0
3 years ago
The aromatic hydrocarbon cymene (C10H14) is found in nearly 100 spices and fragrances, including coriander, anise, and thyme. Th
andrezito [222]

Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

Explanation :

First we have to calculate the heat released by the combustion.

q=c\times \Delta T

where,

q = heat released = ?

c = specific heat of calorimeter = 3.640kJ/^oC

\Delta T = change in temperature = 19.35^oC

Now put all the given values in the above formula, we get:

q=3.640kJ/^oC\times (19.35)^oC

q=70.43kJ

Thus, the heat released by the combustion = 70.43 kJ

Now we have to calculate the molar enthalpy combustion.

\Delta H=-\frac{q}{n}

where,

\Delta H = molar enthalpy combustion = ?

q = heat released = 70.43 kJ

n = number of moles cymene = \frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=\frac{1.608g}{164.22g/mol}=0.009792mole

\Delta H=-\frac{70.43kJ}{0.009792mole}=-7193kJ/mole

Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

4 0
3 years ago
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