REVENUE

1 answer:

OverLord2011 [107]3 years ago

5 0

You should put at least 400 in the savings Which impact did WWII have on the U.S?
A. The U.S. had to rebuild much of its own infrastructure due to the damages of the War
B. The U.S. had one of the highest death tolls of the War
C. The U.S. decided to not get involved in any
future wars
D. The U.S. experienced large economic growth as a result of their wartime economy

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A package contains 16 candy canes, 6 of which are cracked. If 3 are selected, find the probability of getting exactly two cracke

notsponge [240]

<span>To randomly select 3 out of 16, of which 2 are crached, you need 6C2*10C1=6!/(4!2!) * 10=Cases in which you've selected 2 cracked candy.</span>

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3 years ago

A manufacturer of widgets wants to test a new widget-producing machine to determine if it can make an average of 25 widgets per

klio [65]

Using the t-distribution, it is found that since the p-value is greater than 0.01, there is no evidence that the new machine should be rejected at the 0.01 significance level.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the average is not less than 25, that is:

$H_0: \mu \geq 25$

At the alternative hypothesis, it is tested if the average is less than 25, that is:

$H_1: \mu < 25$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Considering the situation described, the values of the parameters are given as follows:

$\overline{x} = 24.97, \mu = 25, s = 2.16, n = 10$

Hence the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.97 - 25}{\frac{2.16}{\sqrt{10}}}$

t = -0.04

<h3>What is the p-value and the conclusion?</h3>

Using a t-distribution calculator, for a left-tailed test, as we are testing if the mean is less than a value, with 10 - 1 = 9 df and t = -0.04, the p-value is of 0.4844.

Since the p-value is greater than 0.01, there is no evidence that the new machine should be rejected at the 0.01 significance level.

More can be learned about the t-distribution at brainly.com/question/13873630

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3 0

2 years ago

This question, please answer it

kobusy [5.1K]

I don’t really see a question-

5 0

3 years ago

Read 2 more answers

PLEASE HELP (50 points)