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3 years ago

Help please idk how to do math

Mathematics

2 answers:

MAVERICK [17]3 years ago

7 0

Answer:

Step-by-step explanation:

25/9= 2.777

Bumek [7]3 years ago

7 0

That would be C
Because 25/9=2.7
You had to divide that :)

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Please answer asap don’t troll!!!

zubka84 [21]

you will do as you said yes yes i is fine with me but i’m going on the right now so bye bye u it was correct that

8 0

3 years ago

Help me please. Fill in the green box

faust18 [17]

According to the euclidean triangle theorem
9 = z² / 13
z² = 9 x 13 = 117
z = 3 √13

3 0

4 years ago

A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel

Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

$x_{Sh} = x_{o} + v_{Sh}\cdot t$

Submarine

$x_{Su} = x_{o}+v_{Su}\cdot t$

Where:

$x_{o}$ - Position of Diego Garcia island, measured in miles.

$x_{Sh}$ , $x_{Su}$ - Current positions of ship and submarine, measured in miles.

$v_{Sh}$ , $v_{Su}$ - Velocities of ship and submarine, measured in miles per hour.

$t$ - TIme, measured in hours.

If we know that $x_{Sh} - x_{Su} = 241\,mi$ , $v_{Sh} = 19\,\frac{mi}{h}$ and $t = 7\,h$ , then:

$x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t$

We clear now the velocity of submarine:

$\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}$

$v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}$

$v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}$

$v_{Su} = -15.429\,\frac{mi}{h}$

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0

3 years ago

Solve each system of equations; nonlinear algebra 2<br><br> x2 + x + y - 26 = 0<br> x + y = 1

BigorU [14]

Answer:

(5,-4) and (-5,6)

Step-by-step explanation:

Given:

$\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.$

Solve it. First, express y in terms of x from the second equation:

$y=1-x$

Substitute it into the first equation:

$x^2+x+1-x-26=0\\ \\x^2-25=0\\ \\(x-5)(x+5)=0$

Apply zero product property:

$x-5=0\ \text{or}\ x+5=0$

So,

$x=5\ \text{or}\ x=-5$

When $x=5,$ then $y=1-5=-4$

When $x=-5,$ then $y=1-(-5)=6$

We get two solutions: (5,-4) and (-5,6)

8 0

3 years ago

June bought three books. For the first book, she paid one half of her allowance plus $1 more. For the second book, she paid one

inysia [295]

Answer:

$34

Step-by-step explanation:

I'd work backwards.

For the third book, she paid all her remaining money. The problem says she paid "1/2 her leftover money + $3". This means that: (let m = money used to buy book 3)

m = 1/2m + 3

1/2m = 3

m = 6

For the second book: (let n = money before book 2)

n - m (money left after book 2) = 1/2n + 2

1/2n +2 is money used up for book, which is the same as n-m.

n = 1/2n + 2 + m

1/2n = 2 + m = 2 + 6

1/2n =8

n = 16

For the first book, she spent 1/2 her money + 1. If o = money before book 1 (or the whole allowance):

o - n = 1/2o + 1

o = 1/2o + n + 1 = 1/2o + 16 + 1

1/2o = 17

o = 34

Check!

Spent 17 (half 34) + 1 on book 1

16 left

Spent 8 (half 16) +2 on book 2

6 left

Spent 3 (half 6) + 3 on book 3

0 left

4 0

3 years ago