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Mamont248 [21]
2 years ago
7

The graph shows the relationship between time

Mathematics
2 answers:
MrMuchimi2 years ago
6 0

Answer:

Pick two points on the line and determine their coordinates. Determine the difference in y-coordinates of these two points (rise). Determine the difference in x-coordinates for these two points (run). Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

jekas [21]2 years ago
3 0

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

(\stackrel{x_1}{4}~,~\stackrel{y_1}{64})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{96}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{96}-\stackrel{y1}{64}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{4}}}\implies \cfrac{\stackrel{bottles}{32}}{\underset{mins}{2}}\implies \cfrac{\stackrel{bottles}{16}}{\underset{mins}{1}}

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Find 5 solutions to the question.<br><br> Y=-1.5x+2
Black_prince [1.1K]

Answer:

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Step-by-step explanation:

Y=1.5x+2

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>)</u></em></h3>

y=1.5 (1) +2

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<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>2</u></em><em><u>)</u></em></h3>

y=1.5(2)+2

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<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em><em><u>)</u></em></h3>

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y=1.5 (4)+2

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<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em></h3>

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3 years ago
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Alecsey [184]

Answer: Point B

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Viefleur [7K]

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2 years ago
H(t)= (t+3)^2 + 5
oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

\frac{h(-1)-h(-5)}{-1+5}

so we find:

h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9

then the average rate of change becomes:

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