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Tems11 [23]
2 years ago
8

Joe has 1.8 meters of rope. He has to cut pieces of rope that are 0.3 meters long. How many pieces can he cut

Mathematics
1 answer:
RSB [31]2 years ago
5 0

Answer:

6

Step-by-step explanation:

1.8 divided by 0.3 = 6

6 x 0.3 = 1.8

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In this diagram, what is the value of b, correct to the nearest tenth?
tatuchka [14]
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4 0
3 years ago
What is the effect of multiplying both sides of an inequality by a negative number? Explain and give an example.
tester [92]

Answer: You would swap the ineqaulity

Step-by-step explanation:

Multiplying or dividing both sides by a negative number reverses the inequality. This means < changes to >, and vice versa. For example, given that 5 < 8 we can multiply both sides by 6 to obtain 30 < 48 which is still true.

5 0
2 years ago
Can someone help me solve this system of linear equations by the addition method?
schepotkina [342]
4x-8y=4
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X=5/3
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3 0
3 years ago
What is the equation of the line shown in the graph? A function graph of a line with two points (-3,-2) and (-1,2) with an x axi
Svetllana [295]
Y=(1/2 x)-2

My Work:
Say that the slop is "a" and that the y-intercept is "b".

For the slope:
First coordinate equation: -3=-2a+b
Second coordinate equation: -1=2a+b
Combine the equations. -3-(-1)=-2a-(2a)+b-(b)
Break down the parenthesis. -3+1=-2a-2a+b-b
Simplify the equation. -2=-4a
Divide both sides by -4 to get the answer to the slope. a=1/2

For the y-intercept:
Use the second coordinate's equation and the now known slope. -3=-2*1/2+b
Multiply -2 by 1/2 (Order of Operations). -3=-1+b
Add +1 to both sides to cancel the -1. -3+1=b
Finally, solve the solve -3+1 to get the answer to the y-intercept. b=-2
5 0
3 years ago
Read 2 more answers
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
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