A farmer can harvets 2 1/3 acres of corn in 1 day. How many days will it take to harvest 10 1\2 acres

1 answer:

6 0

$10 \frac{1}{2} \div2 \frac{1}{3} = \frac{21}{2} \div \frac{7}{3} = \frac{21}{2} \times \frac{3}{7} = \frac{9}{2} = 4 \frac{1}{2}$
Ans: He will take 4 1/2 days to harvest 10 1/2 acres.

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Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime

Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2$

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

$M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46$

The standard error is

$s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194$

The t-statistic is

$t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52$

The degrees of freedom are

$df=n_1+n_2-2=9+9-2=16$

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0

3 years ago

sam thought of a number between ten and twenty then sam gave a clue when you count by twos and when you count by threes but not

tatuchka [14]

Sorry I do not know the answer to that

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3 years ago

Please help me!!! It’s due Thursday

timama [110]

That should be the answers