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3 years ago

PLZ Help Urgent. 15 POINTS, BRAINLY Guaranteed.

Mathematics

1 answer:

leva [86]3 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{15}{1}$ multiplied by $\frac{1}{3}$

which makes: $\frac{15}{3}$

simplify: 5

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The sum of the present ages of Mark and his mother is 60 years. In 6 years she will be twice as old as he will be. Find their pr

Igoryamba

Answer:

Mark is 18; his mother is 42.

Step-by-step explanation:

In 6 years, 12 years will be added to the total of their ages, so it will be 72. Since this is the total of Mark's age and twice Mark's age, his age at that time will be 72/3 = 24. His mother will be 48 at that time.

Now, they are 6 years younger than that, so they are 18 and 42.

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3 years ago

PLEASE HELP ME WITH THIS MATH PROBLEM

prisoha [69]

Answer:

x= 3.3333333(repeating)

Step-by-step explanation:

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3 years ago

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If the money and interest are left in the bank how much is the total accumulated savings at the end of the second year for a sav

Mekhanik [1.2K]

$\qquad \textit{Compound Interest Earned Amount}\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{current amount}\\
P=\textit{original amount deposited}\to &\$3,500\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=\textit{times it compounds per year}\to &1\\
t=years\to &2
\end{cases}
\\ \quad \\
A=3500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}\implies 3500(1.08^2)$

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3 years ago

A college graduate expect to earn a salary of 50000 during the first year after graduation and receive a 3% raise every year aft

11111nata11111 [884]

65,000 give me a thanks or brainiest answer if this helps!

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3 years ago

The two intervals (114.9, 115.7) and (114.6, 116.0) are confidence intervals (computed using the same sample data) for μ = true

kenny6666 [7]

Answer:

115.3 hertz

Step-by-step explanation:

For either interval, the value of the sample mean is given by the average of the lower and upper bound of the confidence interval. Since both intervals were constructed by using the same sample, both values should be equal.

For the first interval:

$M=\frac{114.9 + 115.7}{2} \\M=115.3\ hertz$

For the second interval:

$M=\frac{114.6 + 116.0}{2} \\M=115.3\ hertz$

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3 years ago