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ivolga24 [154]
3 years ago
14

Solve for x. 12x + 7 < -11

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

x < -3/2

Step-by-step explanation:

e-lub [12.9K]3 years ago
6 0

To solve for x, you need to isolate/get the variable "x" by itself in the inequality:

12x + 7 < -11      Subtract 7 on both sides

12x + 7 - 7 < -11 - 7

12x < -18     Divide 12 on both sides to get "x" by itself

\frac{12x}{12}

x    Simplify the fraction

x       (x is any number less than -3/2)

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— 25 — 3х + 5 or – 3х +5 — 31​
zysi [14]

Answer:

both should

be equal to hope my work is correct or helps

Step-by-step explanation:

first one

-25<-3x+5 subtract 5 from both sides

-25-5=-30

5-5=0

then divide by -3

-30 divided by -3 =10

x=10

so it is equal to not less than

second one

-3x+5<-31

subtract 5 from both sides 5-5=0

-31 -5=-36

then divide both sides by -3

x=12

1

6 0
3 years ago
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valentinak56 [21]

Answer:

29-2(2w)13

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w=52÷29

7 0
3 years ago
Please help I’ll give brainliest
Minchanka [31]

Answer:

the answer which you have opted is perfect

6 0
3 years ago
Read 2 more answers
If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
ira [324]
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
-64+ x = -90.3<br><br><br> PLEASE HELP ASAP!!:))
ludmilkaskok [199]

Answer:

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Step-by-step explanation:

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