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ivolga24 [154]
3 years ago
14

Solve for x. 12x + 7 < -11

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

x < -3/2

Step-by-step explanation:

e-lub [12.9K]3 years ago
6 0

To solve for x, you need to isolate/get the variable "x" by itself in the inequality:

12x + 7 < -11      Subtract 7 on both sides

12x + 7 - 7 < -11 - 7

12x < -18     Divide 12 on both sides to get "x" by itself

\frac{12x}{12}

x    Simplify the fraction

x       (x is any number less than -3/2)

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A rectangle has a perimeter of 30 yards. If one side is 5 yards long, how long is the other side?
vagabundo [1.1K]

Answer:

C. 10

Step-by-step explanation:

5+5=10

10+10=20

10+20=30

5 0
2 years ago
Read 2 more answers
Please help. Will give Brainliest.
san4es73 [151]

Answer:

x = 0

x = 7/5

x = -2/3

Step-by-step explanation:

x2 =0

x=0

5x -7 =0

5x = 7

x = 7/5

3x+2 =0

3x = -2

x = -2/3

These are all the 3 roots of this equation

3 0
3 years ago
If a parabola opens downward, the highest point on the graph is called the ____ of the parabola.
Setler [38]

Answer:

vertex

Step-by-step explanation:

6 0
3 years ago
The length of a rectangle is 7/6 its width, w. Which expression represents the perimeter of the rectangle?
Hitman42 [59]
If the length is 7/6 the width w then the perimeter is w + (7/6)w + w + (7/6w)
= 2((7/6)w + w) = 2w + (14/6)w = (26/6)w = (13/3)w.
So the answer is the last one.
3 0
3 years ago
Thank you for anyone who knows this
katen-ka-za [31]

Answer:  

  • Part (a) Vertex = (-3, -1)
  • Part (b) Vertex = (4, 5)
  • Part (c) function 2; max value = 5

=====================================================

Explanations:

Part (a)

In this case, the vertex is the highest point, so the vertex of function 1 is (-3, -1)

If the parabola was flipped so that it opened upward, instead of downward, then the vertex would be the lowest point.

----------------------------

Part (b)

We could graph this function to see where the highest or lowest point is, but there's another way we could find the vertex using algebra.

The given equation is in the form y = ax^2 + bx + c where in this case

  • a = -2
  • b = 16
  • c = -27

The a and b values are plugged into the formula below to get

h = -b/(2a)

h = -16/(2*(-2))

h = -16/(-4)

h = 4

This is the x coordinate the vertex since the vertex is (h,k)

To find k, we plug that value of h into the original function to find its corresponding y value.

y = -2x^2 + 16x - 27

y = -2(4)^2 + 16(4) - 27

y = -2(16) + 16(4) - 27

y = -32 + 64 - 27

y = 5

We found that h = 4 leads to k = 5. The vertex is (h,k) = (4, 5)

----------------------------

Part (c)

We'll compare the y values of each vertex

  • Function 1 has a vertex of (-3, 1)
  • Function 2 has a vertex of (4, 5)

The vertex with the larger y value is the winner, so that would be function 2. This parabola reaches a higher peak compared to the other curve.

The max value here is y = 5. In other words, it's the maximum output the function can produce.

If you graphed functions 1 and 2 together on the same xy grid (see below), you'll see that the curve for function 2 reaches a higher peak.

7 0
2 years ago
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