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Deffense [45]
3 years ago
7

HELP ASAP!!FIRST CORRECT ANSWER WILL GET BRAINLIEST!!

Mathematics
2 answers:
Rudik [331]3 years ago
4 0
-23 is the answer because it is
earnstyle [38]3 years ago
3 0
-23, hope this helps
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in 2000 you weighed 175 pounds. in 2001 you weighed 62 pounds, and in 2002 you weighed 154 pounds. how many pounds did you lose
never [62]
You should get the answer 154 afte u subtract and at that school be your answer
6 0
2 years ago
Find 3rd and 5th form by using nth term formula tn=a+(n-1)d when tn=a+(n-1)d when a=2 and d=3.​
lawyer [7]

Answer:

t3 = 8, t5 = 14

Step-by-step explanation:

t3 = 2 + (3-1) × 3

t3 = 2 + (2) × 3

t3 = 2 + 6

t3 = 8

t5 = 2 + (5-1) × 3

t5 = 2 + (4) × 3

t5 = 2 + 12

t5 = 14

8 0
3 years ago
Use this picture to solve for X
Zepler [3.9K]

Answer:

x=2

Step-by-step explanation:

i would set up a system of equation using the pythagorean theorem:

1^2+x^2=z^2

4^2+x^2=y^2

Add up these equations to get:

17+2x^2=y^2+z^2

But notice that

y^2+z^2=5^2

So you can substitute

17+2x^2=25

2x^2=8

x^2=4

x=2

:)

8 0
2 years ago
If f(x) and its inverse function, f(x), are both plotted on the same coordinate plane, where is their point of intersection?
Tcecarenko [31]

Answer:

(2,2)

Step-by-step explanation:

The graph of a function and that of its inverse should be always symmetric around the line y = x (goes at 45 degrees and crosses the origin of coordinates).

Therefore any intersection of the graphs must lie on the line y = x, which forces the x value of the intersection point to be the same as the y-value.

The only option shown where x and y have the same numerical value is the third listed option : (2,2)

7 0
2 years ago
{1, 5, 10, 15} {1, 3, 5, 7} Which of the following shows the union of the sets?
maria [59]

Answer:

{1, 5}

Step-by-step explanation:

the union is all the values in both sets. The only shared numbers in these two sets are 1, and 5. therefore, the union of the sets is {1, 5}

Hope this helps have a great day! <3

also, pls mark brainliest!!

7 0
2 years ago
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