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Andrew [12]
2 years ago
10

In graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded ad labeled B, and the area where f(x) and g

(x) have shading in common is labeled AB
the graph represents which system of inequalities?

y≤-2x+3
y≤x+3

y≥-2x+3
y≥x+3

y≤-3x+2
y≤-x+2

y>-2x+3
y>x+3​​​

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
5 0

Answer:

The graph represents the system of inequalities y ≤ -3x + 2 and y ≤ -x + 2 ⇒ C

Step-by-step explanation:

From the given figure

∵ The direction of each line is to left

∴ The slopes of the lines are negative

∵ The slope of the line is the coefficient of x

∴ The coefficient of x in each inequality is negative ⇒ (1)

∵ The two lines intersect the y-axis at the point (0, 2)

∴ The y-intercept of the two lines is (0, 2)

∵ The y-intercept is the numerical term in the equation

∴ The numerical term in each inequality is 2 ⇒ (2)

∵ The two lines are solids

∵ The shaded area of each one is under the line

∴ The sign of inequality in both equations is ≤ ⇒ (3)

→ Look at the answer and find which one has the 3 conditions above

∵ y ≤ -3x + 2 and y ≤ -x + 2

∴ m = -3 and m = -1 ⇒ negative coefficients of x

∴ b = 2 ⇒ numerical term

∵ The sign of inequality is ≤

∴ The graph represents the system of inequalities y ≤ -3x + 2 and y ≤ -x + 2

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Step-by-step explanation:

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

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