Sent a picture of the solution to the problem (s).
Not the best handwriting but I hope it helped!
Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
-DIVIDE- the area of a triangle by the -BASE-
, and -MULTIPLY- the result by -2-
Explanation:
Thats because the formula for the area of a triangle is 1/2 x base x height OR (much not confusing formula) BASE x HEIGHT divided by 2
Mark me brainliest tysm! Have a nice day
