All categories

3 years ago

Please help will Mark brainliest if correct

Mathematics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

A = 70 degrees

Step-by-step explanation:

the line that A and 110 degrees makes is a straight line, or 180. So, you just subtract 110 from 180:

180 - 110 = 70

Let me know if you need any more help :)

You might be interested in

During the Indy 500, the winning car traveled at an average constant speed of 232 miles per hour. The equation d = 232t represen

nika2105 [10]

Answer:

the answer should be C

Step-by-step explanation:

This is because the average speed is 232 miles an hour meaning it would cover 232 miles in an hour span.

Hope this helps and don't forget to hit that heart :)

4 0

4 years ago

Make x the subject of these equations.

shepuryov [24]

$(1)a(x + b) = c \\ ax + ab = c \\ ax = c - ab \\ \frac{ax}{a } = \frac{c - ab}{a} \\ x = \frac{c - ab}{a}$

$(2)8(x + a) = b \\ 8x + 8a = b \\ 8x = b - 8a \\ \frac{8x}{8} = \frac{b - 8a}{8} \\ x = \frac{b - 8a}{8}$

$(3)a(x - 7) = b \\ ax - 7a = b \\ ax = b + 7a \\ \frac{ax}{a} = \frac{b + 7a}{a} \\ x = \frac{b + 7a}{a}$

$(4)c(2 + x) = 6 \\ 2c + cx = 6 \\ cx = 6 - 2c \\ \frac{cx}{c} = \frac{6 - 2c}{c} \\ x = \frac{6 - 2c}{c}$

8 0

4 years ago

Read 2 more answers

What numbers do you multiply to find 900 this partical product

Bad White [126]

You mean square root of 900?

I gotcha covered

7 0

2 years ago

Can a few people pls tell me the right answer pls and thank you

sergey [27]

D is the right answers
hope it help... :)

4 0

3 years ago

Solve the system of equations y = 40x2 and y = 19x + 3 algebraically.

ikadub [295]

We have been given a system of nonlinear equations.

$\\y=40x^{2},y=19x+3$

In order to solve this system we can first equate the two equations in order to get a quadratic in x.

$\\40x^{2}=19x+3$

Our next step is to bring all the terms on one side.

$\\40x^{2}-19x-3=0$

Now we have to solve this equation. We can solve it by factoring using the splitting middle term method.

$\\40x^{2}-24x+5x-3=0$

$\\8x(5x-3)+(5x-3)=0$

$\\(8x+1)(5x-3)=0$

Upon setting each of these factors equal to zero using zero product property we get

$\\8x+1=0 \text{ or } 5x-3 = 0$

Upon solving both these equations we get

$\\x=-\frac{1}{8} \text{ or } x=\frac{3}{5}$

Now we can substitute these values of x in the equation

$y=19x+3$

We get

$\text{For }x=- \frac{1}{8} \Rightarrow y=19(- \frac{1}{8})+3= \frac{5}{8}\\$

$\text{For }x= \frac{3}{5}\Rightarrow y=19( \frac{3}{5})+3= \frac{72}{5}\\$

Therefore, our final set of solutions are

$(x,y)=(- \frac{1}{8},\frac{5}{8}) \text{ and } ( \frac{3}{5}, \frac{72}{5})$

6 0

3 years ago

Read 2 more answers