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Dennis_Churaev [7]
3 years ago
7

Help me please i need some help.

Mathematics
2 answers:
vovikov84 [41]3 years ago
6 0

Answer:

12 is the constant

Step-by-step explanation:

12 is the constant number because it doesn't have a variable that can change it

nexus9112 [7]3 years ago
5 0

Answer:

12 is your answer have a good day!!

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Helga [31]

Answer:

1.2

Step-by-step explanation:

6 0
3 years ago
Question 7 of 12. Step 1 of 1
Ostrovityanka [42]

Answer:

97

Step-by-step explanation:

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5 0
4 years ago
Help asap plz!! im doing this test rn and i don’t understand algebra
densk [106]

Answer:

I'm only answering so the guy above me can get brainliest

Step-by-step explanation:

6 0
3 years ago
6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.
nekit [7.7K]

Answer:

a) S= {HH, HT, TH, TT}

b) P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is 2^2 = 4

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

S= {HH, HT, TH, TT}

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

5 0
3 years ago
PLEASE HELP......<br> brainliest....URGENT
evablogger [386]

Answer:

see below

Step-by-step explanation:

1)  see attached image

2) <u> bearings from A to B</u>

Note: bearing is always clockwise from A and from North.

(i)

bearing 180° + 67°

247° from N

(ii)

bearing 148 + 180

328° from N

(iii)

bearing 180 - 21

159° from N

(iv)

39° from N 

(v)

bearing 90 - 40

50° from N

3) <u>back bearing from each diagram on no. 2</u>

<u />

Note: subtract 200 if bearing is more than 180

         add 180 if the bearing is less than 180

(i) 247 - 200 = 47°

(ii) 328 - 200 = 128°

(iii) 159 + 180 = 339°

(iv) 39 + 180 = 219°

(v) 50 + 180 = 230°

5 0
3 years ago
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