C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
Sqrt7 / sqrt 11 = sqrt7/11
3 9/100 would be written as a decimal like this, 3.09. You say three and nine one hundredths. The 9 has to be in the hundredths place, so you put a 0 in front of it. And since the 3 is hole, you put it in front of the decimal point.
X^3 = 16
x^3 = 4^2
x = ∛4^2
x = 4^2/3
answer
B. 4^2/3
------------------
x^5 = 16
x^5 = 2^4
x = 2^4/5
answer
D. x = 2^4/5
See the attached figure to better understand the problem
we know that
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²
<span>AC=8 cm
AB=apothem
BC=9.4/2-----> 4.7 cm
AB</span>²=AC²-BC²-----> 8²-4.7²-----> 64-22.09------> AB²=41.91
AB=√41.91-------> 6.47 cm---------> 6.5 cm
apothem=6.5 cm
the answer is6.5 cm