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Travka [436]
3 years ago
11

Find three consecutive even integers whose sum 72

Mathematics
2 answers:
kotykmax [81]3 years ago
6 0

Answer:

22, 24 and 26.

Step-by-step explanation:

hope that helps, homie.

vova2212 [387]3 years ago
3 0

22, 24, 26

Step-by-step explanation:

<u>2n - 2</u> + <u>2n</u> + <u>2</u><u>n</u><u> </u><u>+</u><u> </u><u>2</u> = 72

6n = 72

n = 72/6

n = 12

∴ so three consecutive even integers whose sum is 72 :

2n - 2

= 2(12) - 2

= 24 - 2

= <u>22</u>

2n

= 2(12)

= <u>24</u>

2n + 2

= 2(12) + 2

= 24 + 2

= <u>26</u>

verification

22 + 24 + 26

= 46 + 26

= 72 ✓✓

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Mr. Trager has $500.00 to spend at a bicycle store. All prices listed below include tax.
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Answer:

He can buy 2 outfits

Step-by-step explanation:

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Will tip
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2443+5433-3444+55555
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Read 2 more answers
4,412.096 rounded to the nearest hundredth.
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We remember that when we round a decimal, we look the number to the right to the one we want to round (in this case, as we want to round to the nearest hundredth, we look at the thousandth position).

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,

1. If the number, is less than 5, we round down, (we leave the same number)

In our exercise, we look at the thousandth position, which is 6. And as it is bigger than 5, we add 1 to the 9 (which is the hundredth position):

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Thus, 4,412.096 rounded to the nearest hundredth is 4,412.1.

8 0
2 years ago
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