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Salsk061 [2.6K]
3 years ago
10

We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal

of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA. We can state ∠C ≅ ∠C using the reflexive property. Therefore, △ACB ~ △DCE by the AA similarity theorem. SSS similarity theorem. AAS similarity theorem. ASA similarity theorem.
Geography
1 answer:
Anvisha [2.4K]3 years ago
5 0

Answer:

your answer is A) AA similarity theorem

Explanation:

have a great day, good luck on your test

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