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rosijanka [135]
2 years ago
7

Anybody have a real answer to the question?

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0
66 inches i believe sorry if im not 100% correct on this.
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Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
2 years ago
Read 2 more answers
If a man earns $420 interest in one year at 7%, what was the amount of money invested?
baherus [9]

Answer:

6,000

Step-by-step explanation:

4 0
3 years ago
Q ÷ 2 -qp ÷ 6; let p = -6 and q = 10
ozzi

Answer:

15

Step-by-step explanation:

1. Plug in the values.

q=10

p=-6

10÷2-(10)(-6)÷6

2. Use PEMDAS.

10÷2+60÷6

5+10

15

5 0
3 years ago
Can someone help me with system of equations?
umka21 [38]

#1)

Answer:

x=1 and y=12

Explanation:

y=5x+7

y=2x+10

This system should use substitution because the value of y is given in terms if x.

Substitution:

5x+7=2x+10

Solve:

3x=3

x=1

Substitute x to solve for y by plugging x into one if the original equations(doesn’t matter which one is used).

y=5x+7

y=5(1)+7

y=5+7

y=12

#2)

Answer:

x=-8 and y=2

Explanation:

y=2x+18

9y=-2x+2

This system also uses substitution. The value of y us already given in terms if c in the first equations, so we will substitute in the second equation.

Substitute:

9(2x+18)=-2x+2

Solve:

18x+162=-2x+2

20x=-160

x=-8

Now that we have the value if x, plug it into one of the original equations(doesn’t matter which equation) and substitute to find y.

y=2x+18

Substitute:

y=2(-8)+18

Solve:

y=-16+18

y=2

7 0
3 years ago
Read 2 more answers
Reduce 720/1080 little cunfused
Veronika [31]
To reduce a fraction, divide the numerator and the denominator equally until they reach the simplest whole number possible. 

In this case, the numerator (720) and the denominator (1080) can both be divided by 360 to get 2/3, our reduced fraction. 

8 0
3 years ago
Read 2 more answers
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