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lesya692 [45]
3 years ago
14

A store sells three types of note cards. There are three sizes of each type. Show two ways to find the total number of notecards

the store sells.
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0
Answer: There are 9 different types of note cards that the store sells.

We can use the Fundamental Counting Principle to determine the total number of options.

There are two different events in this problem. First, there are 3 kinds of cards. Second, there are 3 sizes for each kind.

Simply, multiply the 3 by the other 3 and you have 9 different options.

Just think, each card would have a small, medium and larger option. So there are 3 groups of 3 or 9 total options.
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sample daat reflects shipments received from 3 different vendors Vendor Defective Acceptable 1 16 133 2 25 74 3 24 187 what is c
Sergeu [11.5K]
Question: W<span>hat is the correct hypothesis to determine if quality is associated with vendor?

By looking at other resources, I have found the choices given for this question. They are the following:

a. Null</span>: Quality and source of shipment (vendor) are independent; Alternative: Quality and source of shipment (vendor) are dependent.
b. Null: Quality and source of shipment (vendor) are dependent; Alternative: Quality and source of shipment (vendor) are independent.

The test that would be applicable for this type of data would be the Chi-Square Test for Independence. As the name implies, the null hypothesis should be that the two factors are independent since that will be what we will be testing for.

ANSWER: a. Null: Quality and source of shipment (vendor) are independent; Alternative: Quality and source of shipment (vendor) are dependent.

Question: Calculate the value of the test statistic.

Please refer to the attached document for the complete computation for this part. Generally, we need to find the expected value for each cell in the table and perform some calculation explained in the document.

ANSWER: The test statistic is 12.80.

Question: S<span>pecify decision rule at the 1% significance level.

We can get the critical value for Chi-square tests by first looking for the degree of freedom. We can get the df by evaluating the following expression: (rows-1)*(columns-1). In our case, the number of columns is 2 and the number of rows is 3. The df is therefore (2-1)(3-1)=(1)(2)=2.

We then look at a table to determine what the value at the 1% significance level and df of 2 is.

ANSWER: We reject the null hypothesis if the test statistic is greater than the critical value which is 9.2103.

Question: What is your conclusion?
</span>
Since the test statistic (12.80) is greater than the critical value (9.2103), we can therefore tell that it is in the area for rejection.

Thus, we reject the null hypothesis.

ANSWER:
There is enough evidence to conclude that the quality and source of shipment (vendor) are NOT independent.
Download docx
5 0
3 years ago
Simplify using the distributive property, Show all work (-2x - 9)(-4).
fgiga [73]
-2x(-4)=8x
-9(-4)=36
8x+36 is the answer
6 0
2 years ago
Need help with my practice for a test please give awnser and show your work so i know how to do :)
docker41 [41]

Answer:

Step-by-step explanation:

2 * 2 = 4u² (area of the central square)

2 * 2 : 2 = 2u² (area of one congruent triangle)

4 + 2 + 2 = 8u²

(u = units)

7 0
2 years ago
Read 2 more answers
5. Leyla will roll a number cube 1-4 and flip a coin. The coin can land on heads or tails. If Leyla rolls the number cube once a
mario62 [17]

Answer:

{4H, 4T}

Step-by-step explanation:

The list that contains only the outcomes where the number cube is more than 3 is given below:

Sample space is

= {1,2,3,4}

The results more than 3 is

S = {3}

After this, the sample space i.e. C when the coin is fippled is

C = {H, T}

Here H denotes the Head

T denotes Tail

So, the outcomes would be

= {4} + {H,T}

= {4H, 4T}

3 0
3 years ago
What is the equation of a line that passes through the points (–3, 4) and (2, 8)?
Mrac [35]

Answer:

\frac{y - 4}{x - ( -  3)}  =  \frac{8 - 4}{2  -  (-  3)}  \\  \frac{y - 4}{x + 3}  =  \frac{4}{5}  \\ 5(y - 4) = 4(x + 3) \\ 5y - 20 = 4x + 12 \\  \boxed{4x - 5y + 32 = 0}

<h2>4x-5y+32=0 is the right answer.</h2>
5 0
3 years ago
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