Answers:
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5
Part C: See below.
Explanations:
Part A:
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms:
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8
12y² + 10y – 21
Part B:
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21
Create an algebraic expression:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y² – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26
– 10y – 10y
– 21 + d = 4y³ + 6y² + 6y – 26
+ 21 + 21
d = 4y³ + 6y² + 6y – 5
Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.
Answer:
Step-by-step explanation:
for missing angle of triangle ABC
let the missing angle be y
31+111+x=180(sum of interior angle of a triangle is 180 degree)
142+y=180
y=180-142
y=38 degree
x=y(being alternate angles)
x=38 degree
Exterior angle c = the sun of the two opposite interior angles a and b.
10x -23 = 5x -17 + 7x -26
Combine the right side:
10x -23 = 12x -43
Add 43 to both sides:
10x +20 = 12x
Subtract 10x from both sides:
20 = 2x
Divide both sides by 2
X = 10
Now you have x replace it in the equation for A:
A = 5x -27 = 5(10) -27 = 50-27 = 23
Angle A = 23 degrees.
Answer:
rise is 20 and run is 5 so slope is 4.
I think the slope y-intercept is -5
Answer:
Angles in a pentagon add to 540 degrees.
100+80+160+91+x =540
431+x=540
109=x
Hope this helps!
