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Vikentia [17]
3 years ago
7

You are given m =0.4n - 2/3

Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:8.3

Step-by-step explanation:

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What expressions are equivalent to 5^5 over 5^3
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25 or 5^2 because when you divide two exponents you subtract the exponent parts
7 0
3 years ago
I need help Nvm lml I think I got it
ValentinkaMS [17]

square = 3 \times 3 = 9 \\ rectangle = 2 \times (4 + 3) = 14 \\ the \: whole \: shape = 14 + 9 = 23
6 0
4 years ago
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
Your friend is looking at laptops for college, and is comparing the different screen sizes. Use the diagram and formula below to
elena-14-01-66 [18.8K]
For this case what we should do is write correctly the given equation:
 D ^ 2 = W ^ 2 + H ^ 2
 We substitute the values:
 D = 17inch
 H = 9inch
 Substituting:
 17 ^ 2 = W ^ 2 + 9 ^ 2
 We clear the value of W:
 W = root (17 ^ 2 - 9 ^ 2)
 W = 14.4 inch
 Answer:
 
The width of the laptop screen is:
 
D. W = 14.4 inch
5 0
3 years ago
Read 2 more answers
Please help me tysm!
Nikolay [14]

Answer:

Z.

Step-by-step explanation:

I wrote down the subject with the number of students. I looked one by one to see if the number of students with the subject matched with the graph.  Then I finally found that the last graph matched with what I written down.

7 0
3 years ago
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