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gregori [183]
3 years ago
15

M+ 2/3=1/4m- what the value of ​

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

Answer:

Step-by-step explanation:

subtract m from both sides and you get - 3/4m

divide 2/3 divided by -3/4

-8/9

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The scale drawing of a concrete pad has a length of 9.1 cm, a depth of 2.2 cm and a width of 3.8 cm.
pogonyaev

Answer:

242 cm  

Step-by-step explanation:

1. Find the scale factor

A scale factor (SF) is the ratio of two corresponding lengths in similar figures.

SF = actual distance/scale distance

If the scale width is 3.8 cm,

SF = 418 cm/3.8 cm = 110

2. Calculate the actual depth

110 = actual depth/2.2 cm

Actual depth = 110 × 2.2 cm = 242 cm

8 0
4 years ago
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In a school with 2,000 students, a random sample of 120 students were asked which fruit is their favorite. Their
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567 students would pick orange
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3 years ago
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Please help! if abcd is dilated by a factor of 3, the coordinate of b would be
Nikolay [14]

Answer:

(-6, 6)

Step-by-step explanation:

The coordinates of B to start with is

(-2, 2)

To dilate this by a factor of 3....

-2 * 3 = -6

2 * 3 = 6

The new coordinates of B' would be

(-6, 6)

A few things to know:

- The number 3 is called a "<u>scale factor</u>"

- Dilation means we are multiplying all the (X, Y)'s by the scale factor

- If the scale factor is <u>greater than 1</u>, the size of the shape overall increases

- If the scale factor is <u>less than 1</u>, the size of the shape overall decreases

- If the scale factor is <u>negative</u>, the shape size stays the same. The shape just rotates 180 degrees and moves to the opposite quadrant.

7 0
3 years ago
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Please help asap ill give brainliest :c
Naily [24]

Answer:

Hey there!

You're answer is 1/20.

Step-by-step explanation:

If Mrs. Williams has 1/4 gallon of juice, 1/4 divided by 5 = 1/20.

4 0
3 years ago
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Ayuda necesito resolver este problema con procedimiento ;)
Paraphin [41]

x^3-2x^2+x-1 is one of the prime factors of the polynomial

<h3>How to factor the expression?</h3>

The question implies that we determine one of the prime factors of the polynomial.

The polynomial is given as:

x^8 - 3x^6 + x^4 - 2x^3 - 1

Expand the polynomial by adding 0's in the form of +a - a

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^7 - 4x^6 +x^6 + 2x^5 -2x^5- 3x^4 + 4x^4 + 2x^3 -6x^3+2x^3- x^2  -3x^2 +4x^2-2x+2x-1

Rearrange the terms

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^5 - 3x^4 + 2x^3 - x^2 + 2x^7 - 4x^6 + 4x^4 -6x^3+4x^2-2x+x^6-2x^5+2x^3-3x^2+2x-1

Factorize the expression

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^2(x^6-2x^5+2x^3-3x^2+2x-1) + 2x(x^6-2x^5+2x^3-3x^2+2x-1) + 1(x^6-2x^5+2x^3-3x^2+2x-1)

Factor out x^6-2x^5+2x^3-3x^2+2x-1

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x^2+2x + 1)(x^6-2x^5+2x^3-3x^2+2x-1)

Express x^2 + 2x + 1 as a perfect square

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6-2x^5+2x^3-3x^2+2x-1)

Expand the polynomial by adding 0's in the form of +a - a

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^4-x^3 +x^3-2x^3-x^2 -2x^2 +x+x - 1)

Rearrange the terms

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^3-x^4-2x^3-x^2+x+x^3-2x^2 +x - 1)

Factorize the expression

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3(x^3-2x^2+x-1) -x(x^3-2x^2+x-1)+1(x^3-2x^2+x-1))

Factor out x^3-2x^2+x-1

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3 -x+1)(x^3-2x^2+x-1)

One of the factors of the above polynomial is x^3-2x^2+x-1.

This is the same as the option (c)

Hence, x^3-2x^2+x-1 is one of the prime factors of the polynomial

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
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