1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maxonik [38]
3 years ago
10

23+43=?

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0
The answer will be 66
You might be interested in
48 is what percent of 114
SSSSS [86.1K]
48% is 54.72 of 144
Hope it helped

3 0
4 years ago
Read 2 more answers

The table shows the solution to the equation |2x − 5| − 2 = 3:


11111nata11111 [884]
D. solution is correct
6 0
3 years ago
Read 2 more answers
Problem 7-35 A satellite range prediction error has the standard normal distribution with mean 0 NM and standard deviation 1 NM.
hammer [34]

Answer:

Kindly check explanation

Step-by-step explanation:

For a normal distribution with :

Mean(m) = 0

Standard deviation (s) = 1

Calculate :

(a) less than 1.17 NM Probability

Zscore = (x - m) / s = (1.17 - 0) / 1 = 1.17

P(z < 1.17) = 0.879

(b) between 1.04 NM and 1.99 NM Probability

Zscore = (x - m) / s = (1.04 - 0) / 1 = 1.04

P(z < 1.04) = 0.8508

Zscore = (x - m) / s = (1.99 - 0) / 1 = 1.99

P(z < 1.99) = 0.9767

(0.9767 - 0.8508) = 0.1259

(c) greater than 0.93 NM Probability

P(Z > 0.93) = 1 - p(Z < 0.93) = 1 - 0.8238 = 0.1762

(d) between 0.24 NM and 0.73 NM Probability

P(Z < 0.24) = 0.5948

P(Z <0.73) = 0.7673

0.7673 - 0.5948 = 0.1725

(e) less than or equal to 2.3 NM Probability

P(Z ≤ 2.3) = 0.9893

(f) greater than 2.22 NM or less than .65 NM

P(Z > 2.22) = 1 - p(Z < 2.22) = 1 - 0.9868 = 0.0132

P(Z < 0.65) = 0.7422

0.7422 - 0.0132 = 0.729

(g) greater than or equal to 2.0 NM Probability

P(Z ≥2) = 1 - p(Z ≤ 2)

1 - 0.97725 = 0.02275

3 0
3 years ago
Please help me with this
Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }

Thefore the required answer is ,

\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

4 0
3 years ago
Read 2 more answers
the amount of gasoline at a gas station changes from 58,432.4 gallon to 56,475.2 gallon from 2:00 pm to 4:00 pm. what rational n
jarptica [38.1K]

Answer:

I take it you mean the average gallons lost an hour, in which case you would do 58,432.4 - 56,475.2 to get 1,597.2 to which you divide by 2 getting your final answer of 978.6

4 0
3 years ago
Other questions:
  • How to write a number in 2 other forms
    6·1 answer
  • what is the sum of a 7-term geometric series if the first term is negative 11 the last turn is -45056 and the common ratio is -4
    6·1 answer
  • Mauren usually buy rolled oats from the bulk bin. Today she is considering buying prepackaged rolled oats. The prepackaged rolle
    13·1 answer
  • What is the value of x to the nearest degree?<br><br> a. 24<br> b. 42<br> c. 48<br> d. 84
    6·1 answer
  • What is 12/16 in it's lowest term
    8·2 answers
  • Please help me I need it in five minutes and also please show your work
    12·2 answers
  • Which of these is an example of a literal equation?
    6·1 answer
  • I will upvote!
    8·1 answer
  • Why does the chart not show a.m or p.m?
    15·1 answer
  • Please help with this practice so I can study for my final I am stuggling bad! I will give brainiest for the correct answers!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!