Answer:
The jar has 32 dimes and 18 quarters
Step-by-step explanation:
<u>To solve this problem we can create a system of linear equations in terms of two-variables (say </u>
<u> and </u>
<u>) and solve it.</u> To begin let us analyze the problem further. We know that the values of each coin type are:
Dimes ( ) = $0.10
Quarters( ) = $0.25
Total Value = $7.70
Total Coins = 50
Now let us set up our system of equations as:
Eqn.(1)
Eqn.(2)
Lets take Eqn.(2) and rerrange it to solve for as:
Eqn.(3)
Now lets plug this, in Eqn.(1) so we get the value of as:
Plugging in 
back in Eqn.(3) we finally have:
Thus we conclude that in the jar the coins are:
Dimes ( ) 
Quarters( ) 
Okay so whats the question? That is just a statement
3 times 12 then 3 times 20
3 x 12 = 36
3 x 20 = 60
60 + 36 = 96
96 ÷ 8
Answer:
The answer is none of the above. x= -2.08
Step-by-step explanation:
Answer:
844
Step-by-step explanation:
x = 14
y = 6
(2 * 6)(9 * 6) - (3 * 14) + (17 * 14)
(12)(54) - (42) + (238)
648 - 42 + 238
606 + 238 = 844
844
