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kipiarov [429]
3 years ago
12

Thirty percent of check engine lights turn on after 100,000 miles in a particular model of van. The remainder of vans continue t

o have check engine lights that stay off.
Simulate randomly checking 25 vans, with over 100,000 miles, for check engine lights that turn on using these randomly generated digits. Let the digits 1, 2, and 3 represent a van with check engine light that turn on.

96408 03766 36932 41651 08410

Approximately how many vans will have check engine lights come on?




A. 3

B. 7

C. 8

D. 10

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Count how many times a 1, 2, or 3 appears.  Of the digits, 7 are 1s, 2s, or 3s.

You might be interested in
The slope of the line that passes through the points (-10,y) and (5, 2) is 2/5. What is the value of y?
Murrr4er [49]

Answer:

C, -4

Step-by-step explanation:

slope=change in y/change in x

\frac{2 - y}{5 - ( - 10)}  =  \frac{2}{5}

\frac{2 - y}{5  + 10}  =  \frac{2}{5}

multiply both sides by 2/5

2 - y =  \frac{2}{5} (5 + 10)

simplify the right side. 2/5 × 5 = 2 and 2/5 × 10 = 4

2 - y = 2 + 4

2 - y = 6

bring y to the other side by adding y on both sides

2 = 6 + y

subtract 6 on both sides

2 - 6 = y

so y is -4

7 0
2 years ago
The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
3 years ago
Estimate quotient using multiples, 136÷6
lana66690 [7]
136/6 = 22.6666667......
3 0
3 years ago
Read 2 more answers
Adult tickets to a play cost $1.75 each and student tickets cost $1.25 each. Suppose there are twice as many student tickets sol
nikitadnepr [17]

Answer: the number of adult tickets sold is 400

the number of student tickets sold is 200

Step-by-step explanation:

Let x represent the number of adult tickets sold at the play.

Let y represent the number of student tickets sold at the play.

Adult tickets to a play cost $1.75 each and student tickets cost $1.25 each. If the income from the play was $1,700, it means that

1.75x + 1.25y = 1700 - - - - - - - - - -1

Suppose there are twice as many student tickets sold as adult tickets. This means that

y = 2x

Substituting y = 2x into equation 1, it becomes

1.75x + 1.25 × 2x = 1700= 1700

1.75y + 2.5y = 1700

4.25y = 1700

y = 1700/4.25 = 400

x = y/2 = 400/2 = 200

8 0
3 years ago
What is shaded in here?
Lady_Fox [76]

Answer:

4/100 is the fraction

Step-by-step explanation:

there are four blue blocks shaded out of the 100

7 0
3 years ago
Read 2 more answers
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