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kipiarov [429]
3 years ago
12

Thirty percent of check engine lights turn on after 100,000 miles in a particular model of van. The remainder of vans continue t

o have check engine lights that stay off.
Simulate randomly checking 25 vans, with over 100,000 miles, for check engine lights that turn on using these randomly generated digits. Let the digits 1, 2, and 3 represent a van with check engine light that turn on.

96408 03766 36932 41651 08410

Approximately how many vans will have check engine lights come on?




A. 3

B. 7

C. 8

D. 10

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Count how many times a 1, 2, or 3 appears.  Of the digits, 7 are 1s, 2s, or 3s.

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Which one of the following situations could be represented by a linear function?
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The axis is symmetry for the function f(x) = -x^2-10+16 is x=-5.....
Aleksandr [31]
Axis of symmetry is the line x = h, where (h, k) is the vertex. Plug -5 into the equation to get k.

f(-5)=-(-5)^2-10(-5)+16=-25+50+16=41

(-5, 41)
5 0
4 years ago
FIRST ANSWER GETS BRAINLIEST (ANSWER HAS TO BE IN DETAIL)
agasfer [191]

Answer:

2975.978

Step-by-step explanation:

This is pretty easy, just keep the order going on.

Here is the CORRECT order:

2 Thousand(s)

9 Hundred(s)

7 Ten(s)

5 One(s)

decimal part because there is <em>th</em> after each type of number (ex. thousand<em>th)</em>

9 Tenth(s)

7 Hundredth(s)

8 Thousandth(s)

3 0
2 years ago
Read 2 more answers
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
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