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sdas [7]
2 years ago
5

The product of -3 and -7 is positive. True False

Mathematics
2 answers:
Daniel [21]2 years ago
7 0

Answer:

<em>True</em><em> </em><em>☑</em>

Step-by-step explanation:

- 3 \times  - 7 \\  =   {}^{ + } 21

dmitriy555 [2]2 years ago
3 0
True!! If you multiply -3 x -7 you get 21!!
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Claudia says that she used the GCF to factor the expression 20x + 100xy as 20(x + 5xy). Is she correct? Explain.
Keith_Richards [23]

No, She is not correct.

Step-by-step explanation:

To find the greatest common factor of the expression 20x + 100xy.

Given expression 20x + 100xy.

Let us factor the expression 20x + 100xy.

Now take the common factor in the expression 20x + 100xy.

The common factor is 20x.

So, 20x + 100xy = 20x( 1+ 5y)

But Claudia says that the greatest common factor is 20(x+5xy).

The GCF is wrong.

So, she is not correct.

8 0
3 years ago
Use the distributive property to write an equivalent expression in simplest form.<br> 9(4h+ 9m)
sammy [17]

Answer:

36h+81m

Step-by-step explanation:

9*4h+9*9m=36h+81m

4 0
3 years ago
Read 2 more answers
Solve the triangle. A = 54°, b = 11, c = 8
Delicious77 [7]
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.

For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9 

Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
9/sin54° =  11/sinB
B = 80.4°

9/sin54° = 8/sinC
C = 45.6°

The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
5 0
3 years ago
The figure shown is made of two rectangular prisms.
AlladinOne [14]
I believe it’s expression c sorry if I’m incorrect
6 0
3 years ago
Which of the following equations is perpendicular to the line y = 2x + 8?
EastWind [94]

ya I want to go get back to the school and I will get back to school today I don’t have

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3 years ago
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