Answer:
Diagonal of a rectangular frame = 85 inch
Step-by-step explanation:
Given:
Length of rectangle = 77 inch
Width of rectangle = 36 inch
Find:
Diagonal of a rectangular frame
Computation:
Diagonal of a rectangle = √l² + b²
Diagonal of a rectangular frame = √77² + 36²
Diagonal of a rectangular frame = √5,929 + 1,296
Diagonal of a rectangular frame = √7,225
Diagonal of a rectangular frame = 85 inch
Answer:
The range of data is 9
Step-by-step explanation:
We know that
range of data = maximum value of data - minimum value of data
Now, we can find maximum value of data
and minimum value of data
so,
maximum value of data =9
minimum value of data =0
now, we can plug these values
and we get
range of data =9-0
range of data =9
<span>Algebraic expression of product of 2 and the second
power of y
=> Algebraic expression is a combination of integers (numbers), variables (a,
b, c, x, y, ….), exponent (2 5 3 …) that is a rational number and algebraic
operations like subtraction (-), addition (+), multiplication (x) and division
(/).
=> Product – result of multiplication
=> second power of y = y<span>2
</span>=> 2 x y<span>2
</span>Thus, the algebraic expression of product of 2 and the second power of y
is equals to 2 x y2
</span>
1350 just multiply 30x45 and that the sender
Answer:
The net forces exerted on the horse and cart are not the same, so they are not balanced forces.
Step-by-step explanation:
Please see the Newton's 2nd Law which states that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.
As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.
If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.
If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.
