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Elden [556K]
3 years ago
6

Find the zeros of f(x) = −x3 − 2x2 + 7x − 4. Then describe the behavior of the graph of f at each zero. A. 4, −1; As x → −∞, f →

−∞. When −1 < x < 4, f < 0. At x = 4, f is tangent to the x-axis, so when x > 1, f → ∞. B. −4, 1; As x → −∞, f → −∞. When −4 < x < 1, f > 0. At x = 1, f is tangent to the x-axis, so when x > 1, f → −∞. C. 4, −1; As x → −∞, f → ∞. When −1 < x < 4, f > 0. At x = 4, f is tangent to the x-axis, so when x > 1, f → ∞. D. −4, 1; As x → −∞, f → ∞. When −4 < x < 1, f < 0. At x = 1, f is tangent to the x-axis, so when x > 1, f → −∞.
Mathematics
1 answer:
dybincka [34]3 years ago
3 0
Wait what is this lol??.
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A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro
pshichka [43]

Answer:

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed \frac{dx}{dt} = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}

(h)\frac{dh}{dt}=(x)\frac{dx}{dt}

(h)\frac{dh}{dt}=rx

\frac{dh}{dt}=\frac{rx}{h}

When automobile is 30 miles past the intersection,

For x = 30

\frac{dh}{dt}=\frac{30r}{h}

Since h=\sqrt{d^{2}+(30)^{2}}

Therefore,

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

3 0
3 years ago
I the equation 3x^2+6x=12, the value of c is?
ozzi

Answer:

c = -12

Step-by-step explanation:

Quadratic Standard Form: ax² + bx + c

Step 1: Write equation

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Step 2: Subtract 12 on both sides

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sertanlavr [38]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{k = 3}}}}}

Step-by-step explanation:

\sf{4.5 + 1.5k = 18 - 3k}

Move 3k to left hand side and change it's sign

Similarly, move 4.5 to right hand side and change it's sign

\longrightarrow{ \sf{1.5k + 3k = 18 - 4.5}}

Collect like terms

\longrightarrow{ \sf{4.5k = 18 -  4.5}}

Subtract 4.5 from 18

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Hope I helped!

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