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Vikentia [17]
3 years ago
7

What is the solution to the system of equations? 7x-2y= -24 5x+5y=15

Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0
35x -10y=-120
10x +10y= 30

45x=-90
x=-2

5(-2)+5y=15
-10+5y=15

5y=25
y=5

(-2,5): the answer is b
HACTEHA [7]3 years ago
7 0

Answer:

B. (2,-5)

Step-by-step explanation:

I just took the test

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A total of 765 tickets were sold for the school play. They were either adults or students tickets. There were 65 more student ti
Brrunno [24]

Answer: 350 adult tickets

Step-by-step explanation:

(omg I remember this question!)

  • a stands for the number of adult tickets sold

student tickets : a + 65

<em>the equation for the prob: </em>

765 = a + (a + 65)

<em>solve:</em>

combine 'like terms'

1.) 765 = a + a + 65

2.) 765 = 2a + 65

<u>- 65         - 65 </u>

700= 2a

divide by 2

700/2 = 2a/2

<em>(700/2 = 350) </em>

<em>(the "2" in 2a is cancelled out by the other 2)</em>

<u>350 = a </u>

7 0
3 years ago
50 points please answer
inn [45]

Answer:

D. 30 kilometers

Step-by-step explanation:

Add all the given distances relative to the map together:

6.5 + 9.5 + 4 = 20

Multiply that by the scale to convert centimeters to kilometers:

20 x 1.5 = <u>30</u>

Your answer is 30 kilometers.

You also could have gotten the same answer by multiplying each number by the scale and then adding those together but that is slightly more work so the way I showed is more convenient.

6 0
2 years ago
Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0
3 years ago
Which statement is correct?
Andreyy89

Answer:

Correct statements:

Step-by-step explanation:

A line that rises from left to right has a positive slope.

A line that falls from right to left has a negative slope.

A horizontal line has no slope. (slope of 0)

4 0
3 years ago
Please help with this acellus question!
Anna11 [10]

Answer:

The value of x is 5

Step-by-step explanation:

In the given triangle

∵ A segment joining two points lie on the two side

∵ This segment is parallel to the third side

∴ This segment divides the two sides into parts that have the same ratio

→ That means x over 2x - 3 equal to 10 over 14

∵ \frac{x}{2x-3} = \frac{10}{14}

→ By using cross multiplication

∴ 10 × (2x - 3) = x × 14

∴ 10(2x) - 10(3) = 14x

∴ 20x - 30 = 14x

→ Add 30 to both sides

∵ 20x - 30 + 30 = 14x + 30

∴ 20x = 14x + 30

→ Subtract 14x from both sides

∵ 20x - 14x = 14x - 14x + 30

∴ 6x = 30

→ Divide both sides by 6

∴ x = 5

∴ The value of x is 5

6 0
3 years ago
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