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VMariaS [17]
3 years ago
8

What is the slope of a line that travels through (-5,-5) and (-2,-3)?

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0

Answer:

2/3 or 0.66666

Step-by-step explanation:

For any two points, (x1,y1) and (x2,y2), the slope m=(y2-y1)/(x2-x1)

m=(-3-(-5))/(-2-(-5))

m=2/3

iren [92.7K]3 years ago
3 0

Answer:

m (slope) = 2/3

Step-by-step explanation:

m= change in y / change in x

m= y2-y1 / x2-x1

m= -3-(-5) / -2-(-5)

m= 2/3

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set them equal to their sum. which in this case is 141 then solve for x and plug it into your original equation to get your answer.

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Taylor does jumping jacks at a rate of 50 jumping jacks per minute. If Taylor completes her jumping jacks at a constant rate and
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Answer:

3 minutes

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150/50

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Consider the words typically associated with geometry. Are there any words that would be hard to precisely define? What words ca
LiRa [457]
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3 years ago
Read 2 more answers
Pahelp badly needed!!!!​
Novosadov [1.4K]

Answer:

Step-by-step explanation:

1. 2x - 28

2. 6x3 - 4x2 + 2x

3. x2 + 7x + 12

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Answer the question in the picture
nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

Finally,

\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73

4 0
3 years ago
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