Answer:
1a) 93ten
1b) 135eight
2a) 565ten
2b) 769ten
Step-by-step explanation:
1a)
1011101
7 digits long the first digit (the one that is most far right) is the ones digit or 2^0 digit and so the last digit (the most far left) is 2^6.
So to put the number in base 10 we do:
1(2^6)+0(2^5)+1(2^4)+1(2^3)+1(2^2)+0(2^1)+1(2^0)
=64+0+16+8+4+0+1
=64+16+8+4+1
=(64+16)+(8+4+1)
=80+13
=93
1b)
93
What is the hightest power of 8 in 93?
8^x=93
8^1=8
8^2=64
8^3 would be a factor of 8 too much
So how many 8^2 's are in 93?
64 goes into 93 how many times?
It's once with a remainder of 93-64=29.
So now 29...what is the highest power of 8 that goes into 29? 8^1=8.
How many times? 3(8)=24 with remainder 5.
So 93=1(8^2)+3(8^1)+5(8^0).
93=135eight
2a) 2341six
2(6^3)+3(6^2)+4(6^1)+1(6^0)
2(216)+3(36)+4(6)+1
432+108+24+1
540+25
565
2b) 30001four
3(4^4)+0(4^3)+0(4^2)+0(4^1)+1(4^0)
3(256)+0+0+0+1
768+1
769
Answer:
-24x+2y I think that's the answer
<span>Your answer is -0.5 hope it helps:)
Also, I changed my pfp so know it's not team 10 no more</span>
Answer:
Step-by-step explanation:
The picture of the question in the attached figure
we know that
In the right triangle of the figure
----> by SOH (opposite side divided by the hypotenuse)
using a calculator
Answer:
Angle N should be 64
Step-by-step explanation:
A triangle adds up to 180. So triangle JKL already has 60 towards 180. Triangle ONM already has 56 towards 180. So you have to find the other value needed in order to make 180. 56+60= 116 so we need to find the other angle to make 180. To do so just subtract 180-116 and that gives tou the answer 64 so that would be Angle N
