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3 years ago

I have finals pls help

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

5 0

Answer:

38.28 .........................

jok3333 [9.3K]3 years ago

4 0

Answer:

57.13..................................................

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NEED HELP evaluate a+b/c if a = -28 b = -35 and c = -3

monitta

Answer:

Step-by-step explanation:

(-28-35)/-3

-63/-3

7 0

3 years ago

Line A passes through the points (-8, 5) and (-5, 4). Line B passes through the points (0, 1) and (4, -1). Which of the followin

horrorfan [7]

$\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{\LARGE Line B}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{-1 -1}{4 +0}\implies -\cfrac{1}{2}$

keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.

8 0

2 years ago

2010 0.15

aniked [119]

Answer:

it is a :) hope this helped :)

Step-by-step explanation:

4 0

3 years ago

What is the distance between the y-intercepts of the lines? Adding a picture please help

DerKrebs [107]

The equation of a line is:

y = mx + c

The m is the gradient of the line, and the c is the y-intercept of the line

That means that the y-intercept of [y = -4x + 3] is 3

and the y-intercept of [y = -4x + 4] is 4

So the distance between the two y-intercepts is:

4 - 3 = 1

6 0

3 years ago

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations.

Nostrana [21]

$x^3-27i=0$
$x^3=27i$
$x^3=27e^{i\pi/2}$
$x=\left(27e^{i\pi/2}\right)^{1/3}$
$x=3e^{i(\pi/2+2\pi k)/3}$
$x=3e^{i\pi(4k+1)/6}$

where $k\in\{0,1,2\}$ . This means you have

$x=3e^{i\pi/6}=\dfrac32(\sqrt3+i)$
$x=3e^{i5\pi/6}=\dfrac32(-\sqrt3+i)$
$x=3e^{i9\pi/6}=-3i$

as the solutions to the original equation.

4 0

3 years ago

I have finals pls help​

I have finals pls help