Answer:
The graph in the attached figure
Step-by-step explanation:
we have
This is a linear equation (the graph is a line)
To identify the graph find out the intercepts
<u><em>Find out the y-intercept</em></u>
The y-intercept is the value of y when the value of x is equal to zero
For x=0
The y-intercept is the point (0,-4)
<u><em>Find out the x-intercept</em></u>
The x-intercept is the value of x when the value of y is equal to zero
For y=0
The x-intercept is the point (5.33,0)
therefore
The graph in the attached figure
Answer:
The red square because if u cut it from the side u get to triangles.
Step-by-step explanation:
So, -(a-3b) becomes -1(a-3b). Then, this becomes 5a-1a+3b. There is +3b because there is a double negative. So, 5-1=4, so your answer is 4a+3b. Pls brainliest
Answer: at most 15 pairs of socks
Step-by-step explanation:
Let the number of pair of socks of her sister be 
, and let the number of pairs Lucy has be 
.
Since , Lucy has 4 more than 1/3 the number of pairs of socks as her sister, this means that
.............................. equation 1
Also , Lucy has at most 9 pairs of socks , this means that
....................................... equation 2
Equating the two equations , we have
multiply through by 3
subtract 12 from both sides
Therefore , the sister has at most 15 pairs of socks
There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.
You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.
-x^6 + 3x^4 + 4x^2
-x^2(x^4 - 3x^2 - 4)
Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.
-x^2(x^4 - 3x^2 - 4)
-x^2(x^2 - 4)(x^2 + 1)
Now we can use the factors of two perfect squares rule to factor the middle parenthesis.
-x^2(x^2 - 4)(x^2 + 1)
-x^2(x - 2)(x + 2)(x^2 + 1)
We would also want to split the term in the front.
-x^2(x - 2)(x + 2)(x^2 + 1)
(x)(-x)(x - 2)(x + 2)(x^2 + 1)
Now we would set each portion equal to 0 and solve.
First root
x = 0 ---> no work needed
Second root
-x = 0 ---> divide by -1
x = 0
Third root
x - 2 = 0
x = 2
Forth root
x + 2 = 0
x = -2
Fifth and Sixth roots
x^2 + 1 = 0
x^2 = -1
x = +/- 
x = +/- i
