We alosmt there! thx for the help gys

<img src="https://tex.z-dn.net/?f=%5Chuge%5Csf%5Cunderline%7BQuestion%7D" id="TexFormula1" title="\huge\sf\underline{Question}"

vekshin1

${\qquad\quad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

$\qquad \sf \dashrightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } = 34$

[ add 2 on both sides ]

$\qquad \sf \dashrightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } + 2 = 34 + 2$

[ form identity : a² + b² + 2ab ]

$\qquad \sf \dashrightarrow \: {(x)}^{2} + { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2} + 2 \sdot(x) \sdot \bigg(\cfrac{1}{x} \bigg) = 36$

[ a² + b² + 2ab = (a + b)² ]

$\qquad \sf \dashrightarrow \: {\bigg (x + \cfrac{1}{x} \bigg) }^{2} = 36$

$\qquad \sf \dashrightarrow \: {\bigg (x + \cfrac{1}{x} \bigg) }^{} = \sqrt{ 36}$

$\qquad \sf \dashrightarrow \: x + \cfrac{1}{x} = \pm 6$

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

8 0

2 years ago

A finite geometric series is the sum of a sequence of numbers. Take the sequence 1, 2, 4, 8, … , for example. Notice that each n

Anna [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

A triangle can be formed with side lengths 15 15 and 30 true or false

pogonyaev

If you are not talking about a specific then its - True
if you are talking about an equilateral triangle its - false

7 0

3 years ago

2/0 = 32/48 = 30/0. What number shpuld come in place of the zeros?

Anton [14]

Answer:

$\sf \dfrac{2}{3} = \dfrac{32}{48} = \dfrac{30}{45}$

$\sf \rightarrow \dfrac{2}{x} = \dfrac{32}{48}$

$\sf \rightarrow 2(48)= {32x}$

$\sf \rightarrow 32x= 96$

$\sf \rightarrow x = 3$

<u /> $\rightarrow \sf \dfrac{32}{48} = \dfrac{30}{y}$

$\rightarrow \sf {32y} = 30(48)$

$\rightarrow \sf {32y} = 1440$

$\rightarrow \sf y = 45$

8 0

2 years ago

John has two boxes. The first box has 90 spiders. The second box has 44 spiders. Every day, John moves two spiders from the firs

Nuetrik [128]

Answer:

12 Days

Step-by-step explanation:

Let's make some equations out of what they give us

The first equation would be for the first box

90 - 2x

The first box has 90 spiders initially and 2 get removed everyday (each day is represented by variable x)

The second equation would be for the second box

44 + 2x

The second box has 44 spiders initially and 2 get added everyday

Now, we can set them equal to each other

90 - 2x = 44 + 2x

Solve

46 = 4x

x = 11.5

In 11.5 days the spiders would be equal. But this does not mean we are done. We have to find how many days the number of spiders in the second box will be greater than the number in the first box.

The first day that the number of spiders in the second box will be greater than the number in the first box is 12 days. We just rounded up to get the first whole day that it will be greater.

Check:

90 - 2(12) = 44 + 2(12)

90 - 24 = 44 + 24

66 = 68

90 - 2(11.5) = 44 + 2(11.5)

90 - 23 = 44 + 23

67 = 67

We see here that after 11.5 days there is 67 spiders in each box. We then see that after 12 days the second box has 68 spiders and the first box has 66 spiders.

<em>Hope this helps!!</em>

3 0

3 years ago