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nikdorinn [45]
3 years ago
7

- 2.2f + 0.55 f– 15 - 8=

Mathematics
1 answer:
Andrews [41]3 years ago
7 0
Https://photomath.net/s/rRVj6K
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What is the answer?​
DochEvi [55]

Answer:

HL

Step-by-step explanation:

The hypotenuse and the "leg" are congruent...along with the 90 degree angle.

"The HL Postulate states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent." - Calcworkshop

4 0
3 years ago
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PLEASE ANSWER THIS ASAP !!!!
Y_Kistochka [10]

Answer:

y = (1/2)x + 2

Step-by-step explanation:

Find the slope:

Take the rise over run to find this- For every unit it goes up, it goes two units across, so it will be (1/2)

Find the y-intercept:

This is the value of y where the line intersects the y-axis- (0,2), so 2

Substitute these values in for m and b:

y = mx + b

y = (1/2)x + 2

Hope that helps! :)

3 0
3 years ago
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Simplify the expression 6(y - 2)
yuradex [85]

Answer:

6y-12

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Disregard my work, but how do you get the answer? There is also a graph at the bottom which is optional to use.
kakasveta [241]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
\\\\
f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind.

since the original or "parent" function is y = x²−4x+3, if we change the "x" argument to "x-2", we end up with a horizontal shift.

the x-2 part would be in the template the Bx+C part, with B = 1 and C = -2, or a horizontal shift to the right of 2/1 or 2 units.

since the parent function has a point at (2, -1), if we move that horizontally only to the right, we'd end up at (4, -1).
7 0
4 years ago
What is thirty plus ten times five minus forty five divided by five
Zielflug [23.3K]
The answer would be 71
8 0
4 years ago
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