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AveGali [126]
2 years ago
14

Write an equation of the line that passes through (3,1) and (0,10)

Mathematics
1 answer:
tangare [24]2 years ago
4 0

Step-by-step explanation:

use the slope formula

y2-y1 / x2-x1

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STUDY<br> 1. Simplify the expression below<br> 5p + 14p<br> 4(x - 2) + 6x<br> 2. Evaluate
melisa1 [442]

Answer:

(11)(B) Simplify numeric and algebraic expressions using the laws of exponents, including integral ... Evaluate the expression for d = -2, d = 0, and d = 1.

Step-by-step explanation:

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2 years ago
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Consider a steel ball floating on the surface of mercury in a half-filled container. What happens when the rest of the container
Helen [10]

Answer

The steel ball will be caught up in between the mercury and water medium.

Step-by-step explanation:

  • Mercury with a density of 13546 kg/m^3
  • water with a density of 1000 kg/m^3
  • Steel with a density of 8050 kg/m^3

From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.

The steel ball will be caught in between both mixtures as the density of  steel is 8050 kg/m^3.Which  is more than Water but less than Mercury.

8 0
3 years ago
6 Monica reads 15 pages of a mystery book in 9 minutes. What is
Ivan

Answer:

135

Step-by-step explanation:

15 x 9 = 135

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3 years ago
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A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Find the slope between the points (-3, -5) and (2, -5). Enter DNE if the slope between the points is undefined.
svet-max [94.6K]

Answer: The slope is 0

Step-by-step explanation: The coordinates dont change from y=-5 to y=-5

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